In order to determine the correct conclusion about the given reaction, let's analyze the components and the role of the catalyst involved.
The provided reaction is:
[tex]\[ 2 \, H_2O_2(l) \xrightarrow{MnO_2(s)} 2 \, H_2O(l) + O_2(g) \][/tex]
Let's break down the components of this reaction:
1. Reactants and Products:
- The reactants are [tex]\( H_2O_2 \)[/tex] which is in the liquid phase.
- The products are [tex]\( H_2O \)[/tex] in the liquid phase and [tex]\( O_2 \)[/tex] in the gas phase.
2. Catalyst:
- The substance [tex]\( MnO_2 \)[/tex] is used as a catalyst in this reaction and is in the solid phase.
Catalysts are substances that speed up a chemical reaction without being consumed in the process. There are generally two types of catalysts:
- Homogeneous Catalysts: These catalysts are in the same phase as the reactants. If the reactants are in liquid form, the homogeneous catalyst will also be in liquid form.
- Heterogeneous Catalysts: These catalysts are in a different phase than the reactants. In this case, [tex]\( MnO_2 \)[/tex] is solid while the reactants are liquid.
Given that [tex]\( MnO_2 \)[/tex] is a solid catalyst in a reaction with liquid reactants, we can conclude that [tex]\( MnO_2 \)[/tex] is acting as a heterogeneous catalyst in this reaction.
Based on this detailed analysis, the correct conclusion about this reaction is:
- A heterogeneous catalyst is being used in the reaction.
Thus, the correct option is:
- A heterogeneous catalyst is being used in the reaction.
