A boy and his skateboard have a combined mass of 65 kg. What is the speed of the boy and skateboard if they have a momentum of [tex]275 \, \text{kg} \cdot \frac{\text{m}}{\text{s}}[/tex]?

A. [tex]0 \, \text{m/s}[/tex]
B. [tex]0.24 \, \text{m/s}[/tex]
C. [tex]4.2 \, \text{m/s}[/tex]
D. [tex]8.5 \, \text{m/s}[/tex]



Answer :

To find the speed of the boy and the skateboard, we can use the basic equation from physics that relates momentum, mass, and speed. The formula to compute speed ([tex]\(v\)[/tex]) is given by:

[tex]\[ v = \frac{p}{m} \][/tex]

where:
- [tex]\( p \)[/tex] is the momentum,
- [tex]\( m \)[/tex] is the mass.

Given:
- The momentum ([tex]\( p \)[/tex]) is [tex]\( 275 \, \text{kg} \cdot \frac{m}{s} \)[/tex],
- The combined mass ([tex]\( m \)[/tex]) of the boy and the skateboard is [tex]\( 65 \, \text{kg} \)[/tex].

Plugging the values into the formula, we get:

[tex]\[ v = \frac{275 \, \text{kg} \cdot \frac{m}{s}}{65 \, \text{kg}} \][/tex]

Performing the division gives:

[tex]\[ v \approx 4.230769230769231 \, \text{m/s} \][/tex]

Rounding to one decimal place, we find that the speed is approximately [tex]\( 4.2 \, \text{m/s} \)[/tex].

So, the correct answer is:

[tex]\[ 4.2 \, \text{m/s} \][/tex]