Find the area of a regular decagon with an apothem of 5 meters and a side length of 3.25 meters.

[tex]\[
[?] \text{ m}^2
\][/tex]

Round to the nearest tenth.



Answer :

To find the area of a regular decagon, we need to follow these steps:

1. Calculate the perimeter of the decagon:

The perimeter of a regular polygon can be found by multiplying the number of sides by the side length.

Given:
- The number of sides [tex]\( n = 10 \)[/tex] (since it's a decagon)
- The side length [tex]\( s = 3.25 \)[/tex] meters

Perimeter [tex]\( P \)[/tex] is calculated as follows:
[tex]\[ P = n \times s = 10 \times 3.25 = 32.5 \text{ meters} \][/tex]

2. Calculate the area of the decagon:

The area [tex]\( A \)[/tex] of a regular polygon can be found using the formula:
[tex]\[ A = \frac{1}{2} \times \text{perimeter} \times \text{apothem} \][/tex]

Given:
- Apothem [tex]\( a = 5 \)[/tex] meters

Plugging in the values we have:
[tex]\[ A = \frac{1}{2} \times 32.5 \times 5 = 81.25 \text{ square meters} \][/tex]

3. Round the area to the nearest tenth:

The area calculated is 81.25 square meters. When rounding to the nearest tenth, we inspect the hundredths place, which is 5 in this case, prompting us to round up.

Therefore:
[tex]\[ A \approx 81.2 \text{ square meters} \][/tex]

Final result:

So, the area of the regular decagon is [tex]\( 81.2 \)[/tex] square meters when rounded to the nearest tenth.