Simplify: [tex]x^{\frac{1}{3}}\left(x^{\frac{1}{2}}+2 x^2\right)[/tex]

A. [tex]x^{\frac{1}{4}}+2 x^{\frac{2}{3}}[/tex]
B. [tex]x^{\frac{2}{4}}+2 x^{\frac{7}{3}}[/tex]



Answer :

To simplify the expression [tex]\( x^{\frac{1}{3}}\left(x^{\frac{1}{2}} + 2x^2\right) \)[/tex], follow these steps:

1. Distribute [tex]\( x^{\frac{1}{3}} \)[/tex] across the terms inside the parentheses:
[tex]\[ x^{\frac{1}{3}} \cdot x^{\frac{1}{2}} + x^{\frac{1}{3}} \cdot 2x^2 \][/tex]

2. Simplify each term by adding the exponents (since the bases are the same):

- For the first term [tex]\( x^{\frac{1}{3}} \cdot x^{\frac{1}{2}} \)[/tex]:
[tex]\[ x^{\frac{1}{3} + \frac{1}{2}} \][/tex]
Add the exponents:
[tex]\[ \frac{1}{3} + \frac{1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} \][/tex]
So the first term simplifies to:
[tex]\[ x^{\frac{5}{6}} \][/tex]

- For the second term [tex]\( x^{\frac{1}{3}} \cdot 2x^2 \)[/tex]:
[tex]\[ 2 \cdot x^{\frac{1}{3} + 2} \][/tex]
Add the exponents:
[tex]\[ \frac{1}{3} + 2 = \frac{1}{3} + \frac{6}{3} = \frac{7}{3} \][/tex]
So the second term simplifies to:
[tex]\[ 2x^{\frac{7}{3}} \][/tex]

3. Combine the simplified terms:
[tex]\[ x^{\frac{5}{6}} + 2x^{\frac{7}{3}} \][/tex]

Thus, the simplified expression is:
[tex]\[ x^{\frac{5}{6}} + 2x^{\frac{7}{3}} \][/tex]