12. [tex]p(x)[/tex] is a polynomial of degree 1, and [tex]q(x)[/tex] is a polynomial of degree 2. What kind of polynomial is [tex]p(x) \times q(x)[/tex]?



Answer :

Sure, let's analyze the problem step-by-step.

1. We start by considering the given polynomials:
- [tex]\( p(x) \)[/tex] is a polynomial of degree 1. We can generally represent this as [tex]\( p(x) = ax + b \)[/tex] where [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants.
- [tex]\( q(x) \)[/tex] is a polynomial of degree 2. We can generally represent this as [tex]\( q(x) = cx^2 + dx + e \)[/tex] where [tex]\( c \)[/tex], [tex]\( d \)[/tex], and [tex]\( e \)[/tex] are constants.

2. To find the product [tex]\( p(x) \times q(x) \)[/tex], we multiply these polynomials together:
[tex]\[ p(x) \times q(x) = (ax + b) \times (cx^2 + dx + e) \][/tex]

3. We expand this product by distributing each term in [tex]\( p(x) \)[/tex] across each term in [tex]\( q(x) \)[/tex]:
[tex]\[ (ax + b) \times (cx^2 + dx + e) = ax \cdot cx^2 + ax \cdot dx + ax \cdot e + b \cdot cx^2 + b \cdot dx + b \cdot e \][/tex]

4. Simplify this by combining like terms:
[tex]\[ = acx^3 + adx^2 + aex + bcx^2 + bdx + be \][/tex]

5. Combining the terms, we organize them by the powers of [tex]\( x \)[/tex]:
[tex]\[ = acx^3 + (ad + bc)x^2 + (ae + bd)x + be \][/tex]

6. The highest degree term in the expanded polynomial is [tex]\( acx^3 \)[/tex], which indicates that the leading term has an exponent of 3.

Thus, the result of multiplying [tex]\( p(x) \)[/tex] and [tex]\( q(x) \)[/tex] is a polynomial of degree 3.

The key points summarized:
- [tex]\( p(x) \)[/tex] has a degree of 1.
- [tex]\( q(x) \)[/tex] has a degree of 2.
- The product [tex]\( p(x) \times q(x) \)[/tex] has a degree of [tex]\( 1 + 2 = 3 \)[/tex].

Therefore, the polynomial [tex]\( p(x) \times q(x) \)[/tex] is a polynomial of degree 3.