```plaintext
[tex]\[
\begin{array}{l}
5.6 \\
5.6 \\
=\frac{0}{30} \\
\frac{3}{5} \ \textless \ p \ \textless \ \frac{2}{3} \quad 0.6 \ \textless \ p \ \textless \ 0.7 \\
\end{array}
\][/tex]

Which of the following could be a value of [tex]\( p \)[/tex]?

A. [tex]\(\frac{16}{27}\)[/tex]

B. 0.67

C. [tex]\(60\% \, \text{of} \, 516\)[/tex]

D. [tex]\((0.8)^2\)[/tex]

E. [tex]\(\sqrt{\frac{4}{9}}\)[/tex]
```



Answer :

To find which of the given values could be a possible value for [tex]\( p \)[/tex] in the range [tex]\( 0.6 < p < 0.6667 \)[/tex], we need to compare each value to this range. Let's go through them one by one:

1. [tex]\(\frac{16}{27}\)[/tex]:
- Converting this to a decimal, [tex]\(\frac{16}{27} \approx 0.5926\)[/tex].
- This value is less than 0.6, so it is not in the range [tex]\(0.6 < p < 0.6667\)[/tex].

2. [tex]\(0.67\)[/tex]:
- This is a decimal value.
- [tex]\(0.67\)[/tex] is greater than [tex]\(0.6667\)[/tex], so it is not in the range [tex]\(0.6 < p < 0.6667\)[/tex].

3. [tex]\(60\%\)[/tex] (which is the same as [tex]\(\frac{60}{100}\)[/tex] or [tex]\(0.6\)[/tex]):
- This is exactly equal to 0.6.
- Since [tex]\(0.6\)[/tex] is not strictly greater than [tex]\(0.6\)[/tex], it is not in the range [tex]\(0.6 < p < 0.6667\)[/tex].

4. [tex]\((0.8)^2\)[/tex]:
- Calculating this, [tex]\((0.8)^2 = 0.64\)[/tex].
- This value lies within the range [tex]\(0.6 < p < 0.6667\)[/tex]. So, it is a possible value for [tex]\(p\)[/tex].

5. [tex]\(\sqrt{\frac{4}{9}}\)[/tex]:
- Calculating this, [tex]\(\sqrt{\frac{4}{9}} \approx 0.6667\)[/tex].
- This value is exactly the upper bound of the range [tex]\(0.6667\)[/tex], so it is not strictly less than [tex]\(0.6667\)[/tex]. Therefore, it does not fit within [tex]\(0.6 < p < 0.6667\)[/tex].

After evaluating all the given values, the only value that satisfies [tex]\(0.6 < p < 0.6667\)[/tex] is:
[tex]\[ (0.8)^2 = 0.64 \][/tex]

Thus, the value of [tex]\( p \)[/tex] that fits the given range is [tex]\( 0.64 \)[/tex].