To solve the given sequence of multiplications systematically, follow these steps:
1. First 11 Multiplications:
Each of these multiplications involves multiplying [tex]\(28\)[/tex] by [tex]\(80\)[/tex].
[tex]\[
28 \cdot 80 = 2240
\][/tex]
Repeated 11 times:
[tex]\[
28 \cdot 80 = 2240
\][/tex]
So, we get:
[tex]\[
2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240
\][/tex]
2. Next 2 Multiplications:
Each of these multiplications involves multiplying [tex]\(38\)[/tex] by [tex]\(0\)[/tex]. Any number multiplied by [tex]\(0\)[/tex] is [tex]\(0\)[/tex].
[tex]\[
38 \cdot 0 = 0
\][/tex]
Repeated 2 times:
[tex]\[
38 \cdot 0 = 0
\][/tex]
So, we get:
[tex]\[
0, 0
\][/tex]
3. Next Multiplication:
The multiplication [tex]\(43.50 \times 3\)[/tex]:
[tex]\[
43.50 \times 3 = 130.5
\][/tex]
4. Next 5 Multiplications:
The next value is simply [tex]\(43.50\)[/tex].
[tex]\[
43.50
\][/tex]
and the following value involves multiplying [tex]\(40.5\)[/tex] by [tex]\(0\)[/tex]. Any number multiplied by [tex]\(0\)[/tex] is [tex]\(0\)[/tex].
[tex]\[
40.50
\][/tex]
Followed by three more occurrences of [tex]\(43.50\)[/tex]:
[tex]\[
43.50, 43.50, 43.50
\][/tex]
So, we get:
[tex]\[
43.5, 40.5, 43.5, 43.5, 43.5
\][/tex]
5. Last Multiplication:
The last multiplication involves multiplying [tex]\(37.8\)[/tex] by [tex]\(1\)[/tex]:
[tex]\[
37.80
\][/tex]
Putting it all together, the complete sequence of results is:
[tex]\[
2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 2240, 0, 0, 130.5, 43.5, 40.5, 43.5, 43.5, 43.5, 37.8
\][/tex]
