Instructions: Use the given information to answer the questions and interpret key features. Use any method such as graphing or solving. Round to one decimal place, if necessary.

An irrigation system (sprinkler) has a parabolic pattern. The height, in feet, of the spray of water is given by the equation [tex]h(x)=-x^2+10x+7.5[/tex], where [tex]x[/tex] is the number of feet away from the sprinkler head (along the ground).

- The irrigation system is positioned 7.5 feet above the ground to start.
- The spray reaches a maximum height of 32.5 feet at a horizontal distance of 5 feet away from the sprinkler head.
- The spray reaches all the way to the ground at about ___ feet away.



Answer :

To solve the problem, let's interpret and calculate key features step by step using the information from the given equation [tex]\( h(x) = -x^2 + 10x + 7.5 \)[/tex].

1. Starting Height:
- The irrigation system is positioned 7.5 feet above the ground to start.
This is evident from the constant term in the equation [tex]\( h(x) \)[/tex]. Therefore, the initial height is 7.5 feet.

2. Maximum Height:
- To find the maximum height, we need to find the vertex of the parabola. In a quadratic equation of the form [tex]\( ax^2 + bx + c \)[/tex], the x-coordinate of the vertex can be found using the formula:
[tex]\[ x = -\frac{b}{2a} \][/tex]
Here, [tex]\(a = -1\)[/tex] and [tex]\(b = 10\)[/tex]. Plugging these values into the formula gives:
[tex]\[ x = -\frac{10}{2(-1)} = 5 \][/tex]
So, the maximum height occurs at [tex]\( x = 5 \)[/tex] feet.

- To find the height at this point, substitute [tex]\( x = 5 \)[/tex] back into the equation:
[tex]\[ h(5) = -5^2 + 10(5) + 7.5 = -25 + 50 + 7.5 = 32.5 \][/tex]
Therefore, the maximum height of the spray is 32.5 feet.

3. Ground Reach:
- To determine the horizontal distance at which the spray reaches the ground, we need to solve for [tex]\( x \)[/tex] when [tex]\( h(x) = 0 \)[/tex]. This involves solving the quadratic equation:
[tex]\[ -x^2 + 10x + 7.5 = 0 \][/tex]
Using the quadratic formula [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex], with [tex]\( a = -1 \)[/tex], [tex]\( b = 10 \)[/tex], and [tex]\( c = 7.5 \)[/tex]:
[tex]\[ x = \frac{-10 \pm \sqrt{10^2 - 4(-1)(7.5)}}{2(-1)} = \frac{-10 \pm \sqrt{100 + 30}}{-2} = \frac{-10 \pm \sqrt{130}}{-2} \][/tex]
Solving for both roots:
[tex]\[ x_1 = \frac{-10 + \sqrt{130}}{-2} \approx 10.7 \quad (\text{keeping the positive root}) \][/tex]
Therefore, the spray reaches the ground at approximately 10.7 feet away from the sprinkler head.

To summarize:

- The irrigation system is positioned 7.5 feet above the ground to start.
- The spray reaches a maximum height of 32.5 feet at a horizontal distance of 5 feet away from the sprinkler head.
- The spray reaches all the way to the ground at about 10.7 feet away.