To determine the voltage drop across a resistor, we use Ohm's Law, which states that voltage (V) is directly proportional to the current (I) flowing through the resistor and the resistance value (R) of that resistor.
Ohm's Law is expressed by the formula:
[tex]\[ V = I \times R \][/tex]
In this problem, we are provided with the following information:
- Resistance (R) is 30 ohms.
- Current (I) is 5 amperes.
Now, let's substitute these values into the equation:
[tex]\[ V = 5 \, \text{A} \times 30 \, \Omega \][/tex]
When we multiply the current of 5 amperes by the resistance of 30 ohms:
[tex]\[ V = 150 \, \text{V} \][/tex]
So, the voltage drop across the 30-ohm resistor with a current draw of 5 amperes is:
[tex]\[ V = 150 \, \text{V} \][/tex]
Therefore, the correct answer is:
A. [tex]$30 \times 5 \, \text{A} = 150 \, \text{V}$[/tex]
