Find the 8th term of the arithmetic sequence.

[tex]\[
\begin{array}{l}
5, \frac{11}{3}, \frac{7}{3}, \ldots \\
a_8 = \square
\end{array}
\][/tex]



Answer :

To find the 8th term of the given arithmetic sequence [tex]\(5, \frac{11}{3}, \frac{7}{3}, \ldots\)[/tex], follow these steps:

1. Identify the first term [tex]\(a_1\)[/tex]:

[tex]\[ a_1 = 5 \][/tex]

2. Calculate the common difference [tex]\(d\)[/tex]:

To find the common difference, subtract the first term from the second term:

[tex]\[ d = \left( \frac{11}{3} \right) - 5 \][/tex]

Converting the first term to a fraction:

[tex]\[ 5 = \frac{15}{3} \][/tex]

Now, the common difference is:

[tex]\[ d = \frac{11}{3} - \frac{15}{3} = \frac{11 - 15}{3} = \frac{-4}{3} = -\frac{4}{3} \][/tex]

3. Use the formula for the nth term of an arithmetic sequence:

The formula for the [tex]\(n\)[/tex]-th term [tex]\((a_n)\)[/tex] of an arithmetic sequence is:

[tex]\[ a_n = a_1 + (n - 1) \cdot d \][/tex]

4. Substitute the known values into the formula to find the 8th term ([tex]\(a_8\)[/tex]):

[tex]\[ a_8 = 5 + (8 - 1) \cdot \left( -\frac{4}{3} \right) \][/tex]

5. Simplify the expression:

Calculate [tex]\(8 - 1\)[/tex]:

[tex]\[ 8 - 1 = 7 \][/tex]

Now, multiply 7 by the common difference:

[tex]\[ 7 \cdot \left( -\frac{4}{3} \right) = -\frac{28}{3} \][/tex]

Add this result to the first term:

[tex]\[ a_8 = 5 + \left( -\frac{28}{3} \right) \][/tex]

6. Convert the first term to a fraction and combine:

Convert 5 to a fraction:

[tex]\[ 5 = \frac{15}{3} \][/tex]

Now add the two fractions:

[tex]\[ a_8 = \frac{15}{3} + \left( -\frac{28}{3} \right) = \frac{15 - 28}{3} = \frac{-13}{3} \][/tex]

Therefore, the 8th term of the arithmetic sequence is:

[tex]\[ a_8 = -\frac{13}{3} \][/tex]

Converting [tex]\(-\frac{13}{3}\)[/tex] to a decimal:

[tex]\[ a_8 = -4.333333333333334 \][/tex]

So, the 8th term is [tex]\(-\frac{13}{3}\)[/tex] or approximately [tex]\(-4.33\)[/tex].