To determine the total number of oxygen atoms on the right-hand side of the provided chemical equation, we need to count the oxygen atoms present in each compound on the right-hand side of the equation.
The chemical equation is:
[tex]\[ 2 Ca_2(PO_4)_2(s) + 4 SiO_2(s) + 12 C(s) \rightarrow 4 CaSiO_3(s) + P_4(s) + 12 CO(g) \][/tex]
Let's analyze each compound on the right-hand side:
1. [tex]\[CaSiO_3\][/tex]:
- There are 4 molecules of [tex]\[CaSiO_3\][/tex].
- Each [tex]\[CaSiO_3\][/tex] molecule contains 3 oxygen atoms.
- Therefore, the total number of oxygen atoms from [tex]\[CaSiO_3\][/tex] is:
[tex]\[
4 \text{ molecules} \times 3 \text{ oxygen atoms per molecule} = 12 \text{ oxygen atoms}
\][/tex]
2. [tex]\[CO\][/tex]:
- There are 12 molecules of [tex]\[CO\][/tex].
- Each [tex]\[CO\][/tex] molecule contains 1 oxygen atom.
- Therefore, the total number of oxygen atoms from [tex]\[CO\][/tex] is:
[tex]\[
12 \text{ molecules} \times 1 \text{ oxygen atom per molecule} = 12 \text{ oxygen atoms}
\][/tex]
Summing up the oxygen atoms from both [tex]\[CaSiO_3\][/tex] and [tex]\[CO\][/tex], we get:
[tex]\[
12 \text{ (from CaSiO}_3) + 12 \text{ (from CO)} = 24 \text{ oxygen atoms}
\][/tex]
Thus, the total number of oxygen atoms on the right-hand side of the equation is 24.
