Answer :
To estimate the mean completion time using the midpoints of each class interval in the frequency distribution provided, we'll follow these steps:
1. Identify the midpoints of each class interval:
- For the class interval 9 to 11: midpoint = [tex]\( \frac{9 + 11}{2} = 10 \)[/tex]
- For the class interval 12 to 14: midpoint = [tex]\( \frac{12 + 14}{2} = 13 \)[/tex]
- For the class interval 15 to 17: midpoint = [tex]\( \frac{15 + 17}{2} = 16 \)[/tex]
- For the class interval 18 to 20: midpoint = [tex]\( \frac{18 + 20}{2} = 19 \)[/tex]
- For the class interval 21 to 23: midpoint = [tex]\( \frac{21 + 23}{2} = 22 \)[/tex]
2. Multiply each midpoint by the corresponding frequency:
- For class 9 to 11: [tex]\( 10 \times 8 = 80 \)[/tex]
- For class 12 to 14: [tex]\( 13 \times 9 = 117 \)[/tex]
- For class 15 to 17: [tex]\( 16 \times 7 = 112 \)[/tex]
- For class 18 to 20: [tex]\( 19 \times 5 = 95 \)[/tex]
- For class 21 to 23: [tex]\( 22 \times 3 = 66 \)[/tex]
3. Sum these products to obtain the total sum of products:
[tex]\[ 80 + 117 + 112 + 95 + 66 = 470 \][/tex]
4. Sum the frequencies to find the total number of observations:
[tex]\[ 8 + 9 + 7 + 5 + 3 = 32 \][/tex]
5. Calculate the mean completion time:
- Sum of products = 470
- Total number of observations = 32
Mean completion time = [tex]\( \frac{470}{32} \approx 14.6875 \)[/tex]
6. Round the mean completion time to one decimal place:
[tex]\[ 14.7 \][/tex]
Thus, the estimated mean completion time of the people who took the test is [tex]\( \boxed{14.7} \)[/tex] minutes.
1. Identify the midpoints of each class interval:
- For the class interval 9 to 11: midpoint = [tex]\( \frac{9 + 11}{2} = 10 \)[/tex]
- For the class interval 12 to 14: midpoint = [tex]\( \frac{12 + 14}{2} = 13 \)[/tex]
- For the class interval 15 to 17: midpoint = [tex]\( \frac{15 + 17}{2} = 16 \)[/tex]
- For the class interval 18 to 20: midpoint = [tex]\( \frac{18 + 20}{2} = 19 \)[/tex]
- For the class interval 21 to 23: midpoint = [tex]\( \frac{21 + 23}{2} = 22 \)[/tex]
2. Multiply each midpoint by the corresponding frequency:
- For class 9 to 11: [tex]\( 10 \times 8 = 80 \)[/tex]
- For class 12 to 14: [tex]\( 13 \times 9 = 117 \)[/tex]
- For class 15 to 17: [tex]\( 16 \times 7 = 112 \)[/tex]
- For class 18 to 20: [tex]\( 19 \times 5 = 95 \)[/tex]
- For class 21 to 23: [tex]\( 22 \times 3 = 66 \)[/tex]
3. Sum these products to obtain the total sum of products:
[tex]\[ 80 + 117 + 112 + 95 + 66 = 470 \][/tex]
4. Sum the frequencies to find the total number of observations:
[tex]\[ 8 + 9 + 7 + 5 + 3 = 32 \][/tex]
5. Calculate the mean completion time:
- Sum of products = 470
- Total number of observations = 32
Mean completion time = [tex]\( \frac{470}{32} \approx 14.6875 \)[/tex]
6. Round the mean completion time to one decimal place:
[tex]\[ 14.7 \][/tex]
Thus, the estimated mean completion time of the people who took the test is [tex]\( \boxed{14.7} \)[/tex] minutes.