Consider the system of equations shown.

[tex]\[
\left\{
\begin{array}{c}
y = x + 11 \\
-y = -x + 11
\end{array}
\right.
\][/tex]

What is the solution to this system of equations?

A. [tex]\((0, 11)\)[/tex]
B. [tex]\((0, -11)\)[/tex]
C. No solution
D. Infinitely many solutions



Answer :

To solve the given system of equations:

[tex]\[ \left\{ \begin{array}{c} y = x + 11 \\ -y = -x + 11 \end{array} \right. \][/tex]

we need to determine if there is a common solution for both equations.

First, let's simplify the second equation:

[tex]\[ -y = -x + 11 \][/tex]

Multiply both sides by -1 to solve for [tex]\( y \)[/tex]:

[tex]\[ y = x - 11 \][/tex]

Now we have two equations:

[tex]\[ 1. \; y = x + 11 \][/tex]

[tex]\[ 2. \; y = x - 11 \][/tex]

To find a solution that satisfies both equations, we can set the right-hand sides of these two expressions for [tex]\( y \)[/tex] equal to each other:

[tex]\[ x + 11 = x - 11 \][/tex]

Subtract [tex]\( x \)[/tex] from both sides:

[tex]\[ 11 = -11 \][/tex]

This results in the statement that 11 equals -11, which is clearly false. Since we have reached a contradiction, it indicates that there is no value of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] that can satisfy both equations simultaneously.

Therefore, the solution to this system of equations is:

[tex]\[ \boxed{\text{no solution}} \][/tex]