### Question 7: [tex]\[
d + d + \gamma = 4
\][/tex] Assume [tex]\(\gamma = 1\)[/tex]. [tex]\[
d + d + 1 = 4
\][/tex] Combine like terms. [tex]\[
2d + 1 = 4
\][/tex] Subtract 1 from both sides. [tex]\[
2d = 3
\][/tex] Divide by 2. [tex]\[
d = \frac{3}{2} = 1.5
\][/tex]
### Question 8: [tex]\[
0 + \sqrt{0} + d = 6
\][/tex] Evaluate the square root of 0. [tex]\[
\sqrt{0} = 0
\][/tex] Then plug in the value of [tex]\( d \)[/tex] from question 7. [tex]\[
0 + 0 + d = 6
\][/tex] Simplify the equation. [tex]\[
d = 6
\][/tex]
### Question a: [tex]\[
\alpha + \rho + d
\][/tex] Using the value of [tex]\( d \)[/tex] from question 8. [tex]\[
d = 6
\][/tex] The expression becomes: [tex]\[
\alpha + \rho + 6
\][/tex]
### Question 10: [tex]\[
0 + 2 + d + d
\][/tex] Using the value of [tex]\( d \)[/tex] from question 8. [tex]\[
d = 6
\][/tex] Substitute [tex]\( d \)[/tex] into the equation. [tex]\[
0 + 2 + 6 + 6 = 14
\][/tex] Add all the terms together. [tex]\[
0 + 2 + 6 + 6 = 14
\][/tex]
### Summary of Results: [tex]\[
6. \quad \sqrt{2} + 9 + 2 + 2 = 14.414213562373096
\][/tex] [tex]\[
7. \quad d + d + \gamma = 4 \implies d = 1.5 \quad \text{(assuming } \gamma = 1\text{)}
\][/tex] [tex]\[
8. \quad 0 + \sqrt{0} + d = 6 \implies d = 6
\][/tex] [tex]\[
\text{a.} \quad \alpha + \rho + d = \alpha + \rho + 6
\][/tex] [tex]\[
10. \quad 0 + 2 + d + d = 14 \quad (d = 6)
\][/tex]
