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1. Determine whether or not the equation below is balanced. If it isn't balanced, write the balanced form. Also, identify the reactant(s) and product(s) in this equation. Finally, label this as one of the five types of reactions: combination, decomposition, substitution, double replacement, or reversible.

[tex]Zn + HCl \rightarrow ZnCl_2 + H_2[/tex]

2. Determine whether or not the equation below is balanced. If it isn't balanced, write the balanced form. Also, identify the reactant(s) and product(s) in this equation. Finally, label this as one of the five types of reactions: combination, decomposition, substitution, double replacement, or reversible.

[tex]S_8 + 24F_2 \rightarrow 8SF_6[/tex]

3. Calculate the molecular mass of ferric oxide [tex]\left(Fe_3O_4\right)[/tex].

4. Determine the percentage composition of chlorine in [tex]CaCl_2[/tex].



Answer :

GinnyAnswer
Sure! Let's address each part of the question in detail step-by-step.

1. Determining whether the equation is balanced and identifying components and type of reaction:

Given equation:
[tex]\[ \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]

Checking if the equation is balanced:

- Reactants:
- Zn: 1 atom
- H: 1 atom (from HCl)
- Cl: 1 atom (from HCl)

- Products:
- Zn: 1 atom (in ZnCl2)
- Cl: 2 atoms (in ZnCl2)
- H: 2 atoms (in H2)

We can see that the equation is not balanced because the number of Cl and H atoms on both sides are not equal.

Balanced equation:
[tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]

Now it is balanced:
- Reactants:
- Zn: 1 atom
- H: 2 atoms (from 2 HCl)
- Cl: 2 atoms (from 2 HCl)

- Products:
- Zn: 1 atom (in ZnCl2)
- Cl: 2 atoms (in ZnCl2)
- H: 2 atoms (in H2)

The reactants are Zn and HCl. The products are ZnCl2 and H2. This reaction is a substitution reaction.

2. Determining whether the equation is balanced and identifying components and type of reaction:

Given equation:
[tex]\[ \text{S}_8 + \text{F}_2 \rightarrow 8\text{SF}_6 \][/tex]

Checking if the equation is balanced:

- Reactants:
- S: 8 atoms (in S8)
- F: 2 atoms (in F2)

- Products:
- S: 8 atoms (in 8 SF6)
- F: 48 atoms (in 8 SF6, since each SF6 contains 6 F atoms)

We can see that the equation is not balanced because the number of F atoms on both sides is not equal.

Balanced equation:
[tex]\[ \text{S}_8 + 24\text{F}_2 \rightarrow 8\text{SF}_6 \][/tex]

Now it is balanced:
- Reactants:
- S: 8 atoms (in S8)
- F: 48 atoms (from 24 F2)

- Products:
- S: 8 atoms (in 8 SF6)
- F: 48 atoms (in 8 SF6)

The reactants are S8 and F2. The product is SF6. This reaction is a combination reaction.

3. Calculate the molecular mass of ferric oxide ([tex]\( \text{Fe}_3\text{O}_4 \)[/tex]):

The molecular mass of Fe3O4 is calculated as follows:
- Atomic mass of Fe: 55.845 u
- Atomic mass of O: 15.999 u

[tex]\[ \text{Molecular mass} = 3 \times 55.845 + 4 \times 15.999 = 167.535 + 63.996 = 231.531 \text{ u} \][/tex]

4. Calculate the percentage composition of chlorine in [tex]\( \text{CaCl}_2 \)[/tex]:

- Molar mass of Ca: 40.078 u
- Molar mass of Cl: 35.453 u (each)

Total molar mass of CaCl2 can be calculated as:
[tex]\[ \text{Molar mass of } \text{CaCl}_2 = 40.078 + 2 \times 35.453 = 40.078 + 70.906 = 110.984 \text{ u} \][/tex]

Percentage composition of Cl in CaCl2:
[tex]\[ \text{Percentage of Cl} = \left(\frac{2 \times 35.453}{110.984}\right) \times 100 \approx 63.89\% \][/tex]

So, the chlorine percentage in CaCl2 is approximately 63.888%.

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