5. Puja completed 8 out of 10 math problems, and Ranjulama completed 1 out of 15 similar math problems.

a. Express the number of problems solved by each of them as a fraction.



Answer :

To express the number of problems solved by each of them in fraction, follow these steps:

Step 1: Identify the total number of problems and the number of problems solved by each person.
- Puja solved 8 problems out of a total of 10 problems.
- Ranjulama solved 1 problem out of a total of 15 problems.

Step 2: Write the fraction for each person based on the problems they solved.

For Puja:
- The fraction is given by the number of problems she solved divided by the total number of problems.
- Therefore, Puja's fraction is [tex]\( \frac{8}{10} \)[/tex].

For Ranjulama:
- The fraction is given by the number of problems she solved divided by the total number of problems.
- Therefore, Ranjulama's fraction is [tex]\( \frac{1}{15} \)[/tex].

Step 3: Simplify the fractions if possible.

For Puja:
- [tex]\( \frac{8}{10} \)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2.
- [tex]\( \frac{8 \div 2}{10 \div 2} = \frac{4}{5} = 0.8 \)[/tex]

For Ranjulama:
- [tex]\( \frac{1}{15} \)[/tex] is already in its simplest form, so it remains [tex]\( \frac{1}{15} = 0.06666666666666667 \ldots \)[/tex]

Summary:

- Puja's fraction: [tex]\( \frac{8}{10} \)[/tex] which simplifies to [tex]\( \frac{4}{5} = 0.8 \)[/tex]
- Ranjulama's fraction: [tex]\( \frac{1}{15} = 0.06666666666666667 \ldots \)[/tex]

So, Puja Limbus solved [tex]\( 0.8 \)[/tex] of the problems, and Ranjulama solved [tex]\( 0.0667 \)[/tex] (to four decimal places) of the problems.