An electric company calculates a person's monthly bill from the number of kilowatt-hours (kWh), [tex]\( x \)[/tex], used.

The function [tex] b(x)=\left\{\begin{array}{cc}0.10 x, & x \leq 200 \\ 0.15(x-200)+20, & x\ \textgreater \ 200\end{array}\right. [/tex] determines the bill.

How much is the bill for a person who uses 400 kWh in a month?

A. [tex] \$ 40 [/tex]

B. [tex] \$ 30 [/tex]

C. [tex] \$ 50 [/tex]

D. [tex] \$ 60 [/tex]



Answer :

To determine the bill for a person who uses 400 kWh in a month, let's analyze the given piecewise function [tex]\( b(x) \)[/tex]:

[tex]\[ b(x)= \begin{cases} 0.10x, & \text{if } x \leq 200 \\ 0.15(x-200) + 20, & \text{if } x > 200 \end{cases} \][/tex]

We are given [tex]\( x = 400 \)[/tex] kWh.

Since 400 kWh is greater than 200 kWh, we use the second part of the piecewise function:

[tex]\[ b(x) = 0.15(x - 200) + 20 \][/tex]

Now substitute [tex]\( x = 400 \)[/tex]:

[tex]\[ b(400) = 0.15(400 - 200) + 20 \][/tex]

Calculate the value inside the parentheses:

[tex]\[ 400 - 200 = 200 \][/tex]

Now multiply by 0.15:

[tex]\[ 0.15 \times 200 = 30 \][/tex]

Then add 20 to this result:

[tex]\[ 30 + 20 = 50 \][/tex]

Therefore, the bill for a person who uses 400 kWh in a month is \[tex]$50. So the correct answer is: C. \$[/tex]50