Answer :
Sure, let's break down the solution step-by-step:
### Question 2.1: Calculate the Resultant Force (R)
To find the resultant force [tex]\( R \)[/tex], we need to account for all the forces acting on the car, taking into consideration their direction. The forces are:
- The car's propulsion force: 40 N (in the positive direction)
- The wind force: 15 N (in the negative direction, opposing the car's motion)
- The frictional force: 8 N (also in the negative direction, opposing the car's motion)
We sum these forces algebraically:
[tex]\[ R = \text{Force}_{\text{car}} - \text{Force}_{\text{wind}} - \text{Force}_{\text{friction}} \][/tex]
Substituting the given values:
[tex]\[ R = 40 \, \text{N} - 15 \, \text{N} - 8 \, \text{N} \][/tex]
Calculating the result:
[tex]\[ R = 40 \, \text{N} - 23 \, \text{N} = 17 \, \text{N} \][/tex]
Thus, the resultant force [tex]\( R \)[/tex] is:
[tex]\[ R = 17 \, \text{N} \][/tex]
### Question 2.2: Are the Forces Balanced or Unbalanced? Explain
Forces are considered balanced if the resultant force is zero. When the forces are balanced:
- The object remains in its current state of motion, either at rest or moving with constant velocity.
Conversely, forces are unbalanced when their resultant force is not zero, causing the object to accelerate in the direction of the resultant force.
In this case, the resultant force [tex]\( R \)[/tex] is 17 N, which is not zero. Therefore, the forces are unbalanced.
### Question 2.3: Name the Forces Labelled A, B, and C
To identify the forces:
- Force A corresponds to the propulsion force exerted by the car.
- Force B corresponds to the wind force acting in the opposite direction.
- Force C corresponds to the frictional force between the tyres and the ground.
Thus, the named forces are:
- Force A: "force_car"
- Force B: "force_wind"
- Force C: "force_friction"
In summary:
1. The resultant force [tex]\( R \)[/tex] is 17 N.
2. The forces are unbalanced because the resultant force is not zero.
3. The forces labelled are:
- Force A: force_car
- Force B: force_wind
- Force C: force_friction
### Question 2.1: Calculate the Resultant Force (R)
To find the resultant force [tex]\( R \)[/tex], we need to account for all the forces acting on the car, taking into consideration their direction. The forces are:
- The car's propulsion force: 40 N (in the positive direction)
- The wind force: 15 N (in the negative direction, opposing the car's motion)
- The frictional force: 8 N (also in the negative direction, opposing the car's motion)
We sum these forces algebraically:
[tex]\[ R = \text{Force}_{\text{car}} - \text{Force}_{\text{wind}} - \text{Force}_{\text{friction}} \][/tex]
Substituting the given values:
[tex]\[ R = 40 \, \text{N} - 15 \, \text{N} - 8 \, \text{N} \][/tex]
Calculating the result:
[tex]\[ R = 40 \, \text{N} - 23 \, \text{N} = 17 \, \text{N} \][/tex]
Thus, the resultant force [tex]\( R \)[/tex] is:
[tex]\[ R = 17 \, \text{N} \][/tex]
### Question 2.2: Are the Forces Balanced or Unbalanced? Explain
Forces are considered balanced if the resultant force is zero. When the forces are balanced:
- The object remains in its current state of motion, either at rest or moving with constant velocity.
Conversely, forces are unbalanced when their resultant force is not zero, causing the object to accelerate in the direction of the resultant force.
In this case, the resultant force [tex]\( R \)[/tex] is 17 N, which is not zero. Therefore, the forces are unbalanced.
### Question 2.3: Name the Forces Labelled A, B, and C
To identify the forces:
- Force A corresponds to the propulsion force exerted by the car.
- Force B corresponds to the wind force acting in the opposite direction.
- Force C corresponds to the frictional force between the tyres and the ground.
Thus, the named forces are:
- Force A: "force_car"
- Force B: "force_wind"
- Force C: "force_friction"
In summary:
1. The resultant force [tex]\( R \)[/tex] is 17 N.
2. The forces are unbalanced because the resultant force is not zero.
3. The forces labelled are:
- Force A: force_car
- Force B: force_wind
- Force C: force_friction