What evidence supports a conservation law?

A. [tex]6 CO_2 \rightarrow C_6H_{12}O_6 + 8 O_2[/tex]
B. [tex]6 CO_2 + 6 H_2O + \text{ light} \rightarrow C_6H_{12}O_5 + 6 O_2[/tex]
C. [tex]6 H_2O + \text{ light} \rightarrow C_6H_{12}O_6 + 6 O_2[/tex]
D. [tex]6 CH_2 - 3 C_6H_{12}O_6 + 3 O_2[/tex]



Answer :

Sure, let's examine each chemical equation one by one to check for the conservation of mass by comparing the number of each type of atom on the reactants and products sides.

### Equation 1:
[tex]\[ 6 \text{CO}_2 \rightarrow \text{C}_6 \text{H}_{12} \text{O}_6 + 8 \text{O}_2 \][/tex]

- Reactants:
- Carbon (C): [tex]\(6 \times 1 = 6 \)[/tex]
- Oxygen (O): [tex]\(6 \times 2 = 12 \)[/tex]

- Products:
- Carbon (C): [tex]\(6\)[/tex]
- Hydrogen (H): [tex]\(12 \)[/tex]
- Oxygen (O): [tex]\(6+8 \times 2 = 6 + 16 = 22 \)[/tex]

Since the number of oxygen atoms on the reactant side (12) does not equal the number on the product side (22), this equation does not satisfy the conservation law.

### Equation 2:
[tex]\[ 6 \text{CO}_2 + 6 \text{H}_2 \text{O} + \text{light} \rightarrow \text{C}_6 \text{H}_{12} \text{O}_5 + 6 \text{O}_2 \][/tex]

- Reactants:
- Carbon (C): [tex]\(6 \times 1 = 6 \)[/tex]
- Hydrogen (H): [tex]\(6 \times 2 = 12 \)[/tex]
- Oxygen (O): [tex]\(6 \times 2 + 6 \times 1 = 12 + 6 = 18 \)[/tex]

- Products:
- Carbon (C): [tex]\(6\)[/tex]
- Hydrogen (H): [tex]\(12 \)[/tex]
- Oxygen (O): [tex]\(5 + 6 \times 2 = 5 + 12 = 17 \)[/tex]

Since the number of oxygen atoms on the reactant side (18) does not equal the number on the product side (17), this equation does not satisfy the conservation law.

### Equation 3:
[tex]\[ 6 \text{H}_2 \text{O} + \text{light} \rightarrow \text{C}_6 \text{H}_{12} \text{O}_6 + 6 \text{O}_2 \][/tex]

- Reactants:
- Hydrogen (H): [tex]\(6 \times 2 = 12 \)[/tex]
- Oxygen (O): [tex]\(6 \)[/tex]

- Products:
- Carbon (C): [tex]\(6\)[/tex]
- Hydrogen (H): [tex]\(12 \)[/tex]
- Oxygen (O): [tex]\(6 + 6 \times 2 = 6 + 12 = 18 \)[/tex]

Since the number of oxygen atoms on the reactant side (6) does not equal the number on the product side (18), this equation does not satisfy the conservation law.

### Equation 4:
[tex]\[ 6 \text{CH}_2 \rightarrow 3 \text{C}_6 \text{H}_{12} \text{O}_6 + 3 \text{O}_2 \][/tex]

- Reactants:
- Carbon (C): [tex]\(6 \times 1 = 6 \)[/tex]
- Hydrogen (H): [tex]\(6 \times 2 = 12 \)[/tex]

- Products:
- Carbon (C): [tex]\(3 \times 6 = 18\)[/tex]
- Hydrogen (H): [tex]\(3 \times 12 = 36\)[/tex]
- Oxygen (O): [tex]\(3 \times 6 + 3 \times 2 = 18 + 6 = 24 \)[/tex]

Since the number of carbon, hydrogen, and oxygen atoms on the reactant side (6, 12, 0 respectively) does not equal the number on the product side (18, 36, 24 respectively), this equation does not satisfy the conservation law.

Hence, all these equations do not satisfy the conservation law based on the comparison of atoms of each element on both sides. The equations provided show an imbalance in at least one of the elements, indicating that the mass is not conserved as per the evidence analyzed.