Calvin Peete was a successful golfer who won the Professional Golfers' Association's driving accuracy title every year from 1981 through 1990.

The quadratic expression [tex]-16t^2 + 64t[/tex] represents the height of a golf ball, in feet, [tex]t[/tex] seconds after a person drives the ball. Which equations can be used to find the zeros of the expression?

A. [tex]16t = 0[/tex] and [tex]t + 4 = 0[/tex]
B. [tex]-16t = 0[/tex] and [tex]t^2 - 4 = 0[/tex]
C. [tex]16t = 0[/tex] and [tex]t^2 + 4 = 0[/tex]
D. [tex]-16t = 0[/tex] and [tex]t - 4 = 0[/tex]



Answer :

To identify the equations that can be used to find the zeros of the quadratic expression [tex]\(-16t^2 + 64t\)[/tex], we need to set this expression equal to zero and solve for [tex]\(t\)[/tex]. Let's go through the steps:

1. Set the quadratic expression equal to zero:

[tex]\[ -16t^2 + 64t = 0 \][/tex]

2. Factor the expression:

Notice that we can factor out a common term [tex]\( -16t \)[/tex] from both parts of the expression:

[tex]\[ -16t(t - 4) = 0 \][/tex]

3. Set each factor equal to zero:

For the equation [tex]\( -16t(t - 4) = 0 \)[/tex], according to the zero-product property, if the product of two factors is zero, then at least one of the factors must be zero. So we set each factor to zero:

[tex]\[ -16t = 0 \][/tex]
[tex]\[ t - 4 = 0 \][/tex]

4. Solve each equation:

- For [tex]\( -16t = 0 \)[/tex]:

[tex]\[ t = 0 \][/tex]

- For [tex]\( t - 4 = 0 \)[/tex]:

[tex]\[ t = 4 \][/tex]

So, the equations used to find the zeros of the expression [tex]\(-16t^2 + 64t\)[/tex] are:

[tex]\[ -16t = 0 \quad \text{and} \quad t - 4 = 0 \][/tex]

Therefore, the correct option among the given choices is:

[tex]\[ -16t = 0 \quad \text{and} \quad t - 4 = 0 \][/tex]