How much money will be spent in interest alone over the course of the 3\% 30-year mortgage described in the table?

Mortgage Payments

\begin{tabular}{|r|r|}
\hline \multicolumn{2}{|r|}{ Principal: [tex]$\$[/tex] 200,000.00[tex]$} \\
\hline Interest Rate & Monthly Payment \\
\hline $[/tex]3 \%[tex]$ & $[/tex]\[tex]$ 843$[/tex] \\
\hline [tex]$4 \%$[/tex] & [tex]$\$[/tex] 955[tex]$ \\
\hline $[/tex]5 \%[tex]$ & $[/tex]\[tex]$ 1074$[/tex] \\
\hline
\end{tabular}

[tex]$\$[/tex][?]$



Answer :

To determine how much money will be spent in interest alone over the course of the 30-year mortgage with a 3% interest rate, let's follow this step-by-step solution:

1. Identify Given Information:
- Principal (the initial loan amount): \[tex]$200,000 - Monthly payment: \$[/tex]843
- Interest rate: 3%
- Loan term: 30 years

2. Calculate the Total Amount Paid Over 30 Years:
Each year has 12 months, so in 30 years, there are a total of 30 * 12 = 360 months.
Therefore, the total amount paid over the span of 30 years can be calculated by multiplying the monthly payment by the number of months:
[tex]\[ \text{Total Amount Paid} = 843 \times 360 = \$303,480 \][/tex]

3. Determine the Total Interest Paid:
The total interest paid over the life of the mortgage is the difference between the total amount paid and the principal:
[tex]\[ \text{Total Interest} = 303,480 - 200,000 = \$103,480 \][/tex]

Thus, the amount of money spent in interest alone over the course of the 30-year mortgage with a 3% interest rate is \$103,480.