The figure shows a water tank that consists of a cylinder and a cone. How many cubic feet of water does the tank hold?

The figure shows a water tank that consists of a cylinder and a cone How many cubic feet of water does the tank hold class=


Answer :

Answer:

V = (1/3)π(6²)(8) + π(6²)(10)

= 96π + 360π

= 456π ft³

= about 1,432.57 ft³

Answer:

[tex]408\pi ft^3[/tex] or [tex]1281.770ft^3[/tex]

Step-by-step explanation:

In order to figure out the amount of water that the tank can hold, we need to find the volume of the cone and the cylinder. We can do this by applying the formula for both figures separately given their dimensions to find the volume of each figure, then adding them together:

Cone - [tex]V = \frac{1}{3} \pi r^{2} h[/tex]

Cylinder - [tex]V = \pi r^{2}h[/tex] (area of circle times height)

  • Cone volume = [tex]\frac{1}{3} \pi (6)^2(10)= 120\pi[/tex]
  • Cylinder volume = [tex]\pi (6)^2(8)= 288\pi[/tex]
  • [tex]120\pi +288\pi =408\pi ft^3[/tex] or [tex]1281.770ft^3[/tex]

(Note that the answer must include units, as they are given in this question as cubic feet)