To determine the equivalent weight of Chromium (Cr) in this reaction, follow these steps:
1. Determine the molecular weight of CrO₃:
- The molecular weight of Chromium Trioxide (CrO₃) is given as 100 grams per mole for simplicity's sake (though the exact molar mass is approximately 99.994 g/mol).
2. Identify the change in oxidation state:
- Chromium (Cr) in CrO₃ starts with an oxidation state of +6 (since oxygen is typically -2 and there are three oxygens: [tex]\(3 \times (-2) = -6\)[/tex]; to balance, Cr must be +6).
- In the product, Chromium (Cr) is in its elemental form (Cr), which has an oxidation state of 0.
3. Calculate the change in oxidation number:
- The change in oxidation number for Chromium is from +6 to 0. This is a change of [tex]\(6 - 0 = 6\)[/tex].
4. Determine the equivalent weight of CrO₃:
- The formula for equivalent weight is the molecular weight divided by the change in oxidation number.
- Here, the equivalent weight of CrO₃ is given by:
[tex]\[
\text{Equivalent weight} = \frac{\text{Molecular weight of CrO}_3}{\text{Change in oxidation number}}
\][/tex]
- Plugging in the numbers:
[tex]\[
\text{Equivalent weight} = \frac{100}{6} \approx 16.67 \text{ grams per equivalent}
\][/tex]
Therefore, the equivalent weight of Chromate (CrO₃) in this reaction is 16.67 grams per equivalent.
