To determine how many milliliters of a 0.450 M LiI solution are needed to contain 0.600 moles of LiI, follow these steps for a detailed solution:
1. Understand the relationship between molarity, moles, and volume:
- Molarity (M) is the concentration of a solution and is defined as the number of moles of solute per liter of solution.
- The formula to relate these quantities is:
[tex]\[
\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}}
\][/tex]
2. Rearrange the formula to solve for the volume of the solution in liters:
[tex]\[
\text{Volume (L)} = \frac{\text{moles of solute}}{\text{Molarity (M)}}
\][/tex]
3. Substitute the given values into the formula:
- Given:
- Molarity (M) = 0.450 M
- Moles of LiI = 0.600 moles
[tex]\[
\text{Volume (L)} = \frac{0.600 \text{ moles}}{0.450 \text{ M}}
\][/tex]
4. Calculate the volume in liters:
[tex]\[
\text{Volume (L)} = \frac{0.600}{0.450} = 1.3333 \text{ liters}
\][/tex]
5. Convert the volume from liters to milliliters:
- Since 1 liter is equal to 1000 milliliters,
[tex]\[
\text{Volume (mL)} = 1.3333 \text{ liters} \times 1000 \text{ mL/L} = 1333.3333 \text{ mL}
\][/tex]
6. Round the final answer to match the given options:
- The closest option to 1333.3333 mL is 1330 mL.
Therefore, the answer is:
D) 1330 mL
