Two triangular pyramids are similar. The volume of the larger pyramid is [tex]$729 \, \text{cm}^3$[/tex], and the volume of the smaller pyramid is [tex]$64 \, \text{cm}^3$[/tex]. If the perimeter of the base of the smaller pyramid is 8 cm, what is the perimeter of the base of the larger pyramid?

A. 18 cm
B. [tex]$18 \, \text{cm}^2$[/tex]
C. 27 cm
D. [tex]$27 \, \text{cm}^2$[/tex]



Answer :

To solve the problem of finding the perimeter of the base of the larger pyramid given that the two triangular pyramids are similar, follow these steps:

1. Identify the given data:
- Volume of the larger pyramid: [tex]\( 729 \, cm^3 \)[/tex]
- Volume of the smaller pyramid: [tex]\( 64 \, cm^3 \)[/tex]
- Perimeter of the base of the smaller pyramid: [tex]\( 8 \, cm \)[/tex]

2. Determine the scale factor based on volumes:
- Since the pyramids are similar, the volumes of similar figures are proportional to the cube of their scale factor.
- Let the scale factor be [tex]\( k \)[/tex].
- Then, [tex]\( \left(\frac{\text{volume of the larger pyramid}}{\text{volume of the smaller pyramid}}\right) = k^3 \)[/tex].

Therefore:
[tex]\[ k^3 = \left(\frac{729}{64}\right) \][/tex]

3. Calculate the scale factor [tex]\( k \)[/tex]:
- We find the cube root of the ratio of the volumes:
[tex]\[ k = \left(\frac{729}{64}\right)^{\frac{1}{3}} \][/tex]
[tex]\[ k = 2.25 \][/tex]

4. Calculate the perimeter of the base of the larger pyramid:
- Since the pyramids are similar, the perimeter of the bases are proportional to the linear scale factor [tex]\( k \)[/tex].
- Hence:
[tex]\[ \text{Perimeter of base of larger pyramid} = \text{Perimeter of base of smaller pyramid} \times k \][/tex]
[tex]\[ \text{Perimeter of base of larger pyramid} = 8 \, cm \times 2.25 \][/tex]

Therefore:
[tex]\[ \text{Perimeter of base of larger pyramid} = 18 \, cm \][/tex]

Thus, the perimeter of the base of the larger pyramid is [tex]\( 18 \, cm \)[/tex].

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