Sure! Let's solve the division problem [tex]\( 237 \div 4 \)[/tex] step-by-step:
1. Start by examining the two numbers: 237 (the dividend) and 4 (the divisor).
2. Determine how many times 4 can fit into 237.
3. Perform the division:
- [tex]\( 4 \)[/tex] fits into [tex]\( 23 \)[/tex] five times because [tex]\( 4 \times 5 = 20 \)[/tex].
- Subtract 20 from 23 to get a remainder of [tex]\( 3 \)[/tex].
- Bring down the next digit, which is 7, making it [tex]\( 37 \)[/tex].
4. Now see how many times [tex]\( 4 \)[/tex] can fit into [tex]\( 37 \)[/tex]:
- [tex]\( 4 \)[/tex] fits into [tex]\( 37 \)[/tex] nine times because [tex]\( 4 \times 9 = 36 \)[/tex].
- Subtract 36 from 37 to get a remainder of [tex]\( 1 \)[/tex].
5. Since we have a remainder of [tex]\( 1 \)[/tex], we need to handle the remainder by converting it into decimal:
- To proceed, add a decimal point and bring down a zero, making it [tex]\( 10 \)[/tex].
- [tex]\( 4 \)[/tex] fits into [tex]\( 10 \)[/tex] two times because [tex]\( 4 \times 2 = 8 \)[/tex].
- Subtract 8 from 10 to get a remainder of [tex]\( 2 \)[/tex].
- Bring down another zero, making it [tex]\( 20 \)[/tex].
6. Repeat the process:
- [tex]\( 4 \)[/tex] fits into [tex]\( 20 \)[/tex] five times because [tex]\( 4 \times 5 = 20 \)[/tex].
- Subtract 20 from 20 to get a remainder of [tex]\( 0 \)[/tex].
Thus, [tex]\( 237 \div 4 = 59.25 \)[/tex].
So, the final answer is [tex]\( 59.25 \)[/tex].
