To determine how many moles of nitrogen monoxide (NO) will be generated when 0.83 moles of nitrogen dioxide (NO₂) reacts with water according to the given reaction:
[tex]\[ 3 \text{ NO}_2 + \text{ H}_2\text{O} \rightarrow 2 \text{ HNO}_3 + \text{ NO} \][/tex]
We need to follow these steps:
1. Identify the stoichiometric ratio from the balanced chemical equation. According to the equation, 3 moles of NO₂ produce 1 mole of NO.
2. Determine the number of moles of NO produced using the stoichiometric ratio. If 3 moles of NO₂ produce 1 mole of NO, then 1 mole of NO₂ will produce [tex]\(\frac{1}{3}\)[/tex] mole of NO.
3. Calculate moles of NO from given moles of NO₂:
Given:
- Moles of NO₂ = 0.83
Using the stoichiometric ratio:
[tex]\[
\text{Moles of NO} = \left( \frac{1}{3} \right) \times 0.83
\][/tex]
Simplifying this, we get:
[tex]\[
\text{Moles of NO} = 0.2766666666666666
\][/tex]
This value can be rounded to 0.277 to match the format of the answer choices.
Thus, the number of moles of nitrogen monoxide (NO) generated is approximately 0.277 moles.
The correct answer is:
A. 0.277 moles
