Answer :
To compare the maximum heights and the total distances traveled of Ana's and Taylor's passes, let's analyze the provided data:
For Ana:
- From the table, the vertical heights at various distances [tex]\(x\)[/tex] are given.
- The maximum height achieved by Ana's pass, [tex]\(a(x)\)[/tex], is 36 feet.
- The total distance traveled by Ana's pass is 60 feet.
For Taylor:
- The vertical height for Taylor's pass, [tex]\(t(x)\)[/tex], is given by the equation [tex]\( t(x) = -0.05(x^2 - 50x) \)[/tex].
- The maximum height Taylor's pass achieves is 31.25 feet.
- The total distance traveled by Taylor's pass, determined by solving the roots of the equation, is 50 feet.
From this data, we can compute the differences:
1. The difference in the maximum heights:
[tex]\[ 36 - 31.25 = 4.75 \text{ feet} \][/tex]
2. The difference in the total distances traveled:
[tex]\[ 60 - 50 = 10.0 \text{ feet} \][/tex]
Therefore:
- The difference of the maximum heights is [tex]\( 4.75 \)[/tex] feet.
- The difference of the total distances traveled is [tex]\( 10.0 \)[/tex] feet.
For Ana:
- From the table, the vertical heights at various distances [tex]\(x\)[/tex] are given.
- The maximum height achieved by Ana's pass, [tex]\(a(x)\)[/tex], is 36 feet.
- The total distance traveled by Ana's pass is 60 feet.
For Taylor:
- The vertical height for Taylor's pass, [tex]\(t(x)\)[/tex], is given by the equation [tex]\( t(x) = -0.05(x^2 - 50x) \)[/tex].
- The maximum height Taylor's pass achieves is 31.25 feet.
- The total distance traveled by Taylor's pass, determined by solving the roots of the equation, is 50 feet.
From this data, we can compute the differences:
1. The difference in the maximum heights:
[tex]\[ 36 - 31.25 = 4.75 \text{ feet} \][/tex]
2. The difference in the total distances traveled:
[tex]\[ 60 - 50 = 10.0 \text{ feet} \][/tex]
Therefore:
- The difference of the maximum heights is [tex]\( 4.75 \)[/tex] feet.
- The difference of the total distances traveled is [tex]\( 10.0 \)[/tex] feet.