6 - Radicals

Learning Objective: Simplify a square root or a cube root to determine if the result is an integer.

Which of the following would result in an integer?

a.) [tex]\sqrt{27}[/tex]

b.) [tex]\sqrt{15}[/tex]

c.) [tex]\sqrt{169}[/tex]

d.) [tex]\sqrt{31}[/tex]



Answer :

To determine which of the given options results in an integer, we need to simplify each square root.

Option a.) [tex]\(\sqrt{27}\)[/tex]

- The square root of 27 can be approximated or calculated as follows:
[tex]\[ \sqrt{27} \approx 5.196 \][/tex]
- This is not an integer.

Option b.) [tex]\(\sqrt{15}\)[/tex]

- The square root of 15 can be simplified or approximated as follows:
[tex]\[ \sqrt{15} \approx 3.873 \][/tex]
- This is not an integer.

Option c.) [tex]\(\sqrt{169}\)[/tex]

- The square root of 169 can be simplified as follows:
[tex]\[ \sqrt{169} = 13 \][/tex]
- This is an integer.

Option d.) [tex]\(\sqrt{31}\)[/tex]

- The square root of 31 can be approximated or calculated as follows:
[tex]\[ \sqrt{31} \approx 5.568 \][/tex]
- This is not an integer.

From the above simplifications, we observe that the only option resulting in an integer is:

Option c.) [tex]\(\sqrt{169}\)[/tex]

Thus, the correct answer is:
[tex]\[ \boxed{\sqrt{169}} \][/tex]