2. Write [tex]$1.888 \ldots$[/tex] as a mixed number.

Let [tex]$x = \square$[/tex]

[tex][tex]$10x = \square$[/tex][/tex]

[tex]$10x - x = \square$[/tex]

[tex]$9x = \square$[/tex]

[tex][tex]$x = \square$[/tex][/tex]

So [tex]$1.888 \ldots$[/tex] is equal to [tex]$\square$[/tex]



Answer :

Let’s work through the problem step-by-step to convert the repeating decimal [tex]\(1.888\ldots\)[/tex] to a mixed number.

1. Assign the repeating decimal to a variable:
Let [tex]\(x = 1.888\ldots\)[/tex]

2. Multiply by 10 to shift the decimal point:
[tex]\(10x = 18.888\ldots\)[/tex]

3. Subtract the original [tex]\(x\)[/tex] from this new equation to eliminate the repeating part:
[tex]\(10x - x = 18.888\ldots - 1.888\ldots\)[/tex]

4. Simplify the subtraction:
[tex]\(10x - x = 16.991999999999997\)[/tex]

5. This gives us:
[tex]\(9x = 16.991999999999997\)[/tex]

6. Solve for [tex]\(x\)[/tex] by dividing both sides by 9:
[tex]\(x = \frac{16.991999999999997}{9}\)[/tex]

Thus, the value of [tex]\(x\)[/tex] is approximately:
[tex]\[ x = 1.8879999999999997 \][/tex]

However, to convert to the exact fraction form, we should recognize that [tex]\(x = 1.888\ldots\)[/tex] was the original repeating decimal we started with. To express this as a mixed number:

[tex]\[ 1.888\ldots = 1 + \frac{8}{9} \][/tex]

So, [tex]\(1.888\ldots\)[/tex] as a mixed number is [tex]\(1 \frac{8}{9}\)[/tex].