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If Jules Verne expressed the title of his famous book, Twenty Thousand Leagues Under the Sea, in basic SI units, what would the title be? Round your answer to three significant figures.

[tex]\[
\begin{array}{l}
(1 \text{ league } = 3.45 \text{ mi}, \, 1 \text{ mi} = 1609 \text{ m}) \\
20,000 \times 3.45 \text{ mi} = 69,000 \text{ mi} \\
69,000 \text{ mi} \times 1609 \text{ m/mi} = x \text{ m}
\end{array}
\][/tex]



Answer :

GinnyAnswer
To convert the title "Twenty Thousand Leagues under the Sea" into basic SI units (meters), let's follow these steps:

1. Understand the conversion factors:
- 1 league = 3.45 miles
- 1 mile = 1609 meters

2. Calculate the total distance in leagues:
- The given distance is 20,000 leagues.

3. Convert the distance from leagues to miles:
- Distance in miles = Distance in leagues [tex]\(\times\)[/tex] Conversion factor (league to miles)
- Distance in miles = 20,000 leagues [tex]\(\times\)[/tex] 3.45 miles/league
- Distance in miles = 69,000 miles

4. Convert the distance from miles to meters:
- Distance in meters = Distance in miles [tex]\(\times\)[/tex] Conversion factor (miles to meters)
- Distance in meters = 69,000 miles [tex]\(\times\)[/tex] 1609 meters/mile
- Distance in meters = 111,021,000 meters

5. Round the distance to three significant figures:
- The distance in meters should be rounded to three significant figures.
- 111,021,000 meters rounded to three significant figures is 111,000,000 meters.

Therefore, if Jules Verne expressed the title of his famous book, "Twenty Thousand Leagues under the Sea" in basic SI units, it would be "111,000,000 meters under the Sea."

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