Answer :
Sure, let's go through the solution step by step to determine the units of the given expression.
1. Identify the units in the numerator:
- The first term in the numerator has units of [tex]\(\frac{g}{mL}\)[/tex]. That is, 2.42 [tex]\(\frac{g}{mL}\)[/tex].
- The second term in the numerator has units of [tex]\(\frac{mL}{10^{-3} L}\)[/tex], which simplifies to [tex]\( \frac{1}{10^{-3}} \frac{mL}{L}\)[/tex]. This can be simplified further to [tex]\(10^3 \frac{mL}{L}\)[/tex].
2. Combine the numerator units:
- When we multiply these two terms together, we get [tex]\(\left(2.42 \frac{g}{mL}\right) \left(10^3 \frac{mL}{L}\right)\)[/tex].
- The [tex]\(mL\)[/tex] units cancel each other out, leaving us with [tex]\(2.42 \times 10^3 \frac{g}{L}\)[/tex].
3. Identify the units in the denominator:
- The denominator has units of [tex]\(\frac{g}{mol}\)[/tex], specifically 109.19 [tex]\(\frac{g}{mol}\)[/tex].
4. Combine the units from the numerator and the denominator:
- The effective numerator, after simplifying, has units of [tex]\(\frac{g}{L}\)[/tex].
- The denominator has units of [tex]\(\frac{g}{mol}\)[/tex].
5. Simplify the combined units:
- We now have [tex]\(\frac{g/L}{g/mol}\)[/tex].
- Dividing these units results in: [tex]\(\left(\frac{g}{L}\right) \times \left(\frac{mol}{g}\right) = \frac{mol}{L}\)[/tex].
Therefore, the resulting units for the student's answer are:
[tex]\[ \boxed{\frac{mol}{L}} \][/tex]
1. Identify the units in the numerator:
- The first term in the numerator has units of [tex]\(\frac{g}{mL}\)[/tex]. That is, 2.42 [tex]\(\frac{g}{mL}\)[/tex].
- The second term in the numerator has units of [tex]\(\frac{mL}{10^{-3} L}\)[/tex], which simplifies to [tex]\( \frac{1}{10^{-3}} \frac{mL}{L}\)[/tex]. This can be simplified further to [tex]\(10^3 \frac{mL}{L}\)[/tex].
2. Combine the numerator units:
- When we multiply these two terms together, we get [tex]\(\left(2.42 \frac{g}{mL}\right) \left(10^3 \frac{mL}{L}\right)\)[/tex].
- The [tex]\(mL\)[/tex] units cancel each other out, leaving us with [tex]\(2.42 \times 10^3 \frac{g}{L}\)[/tex].
3. Identify the units in the denominator:
- The denominator has units of [tex]\(\frac{g}{mol}\)[/tex], specifically 109.19 [tex]\(\frac{g}{mol}\)[/tex].
4. Combine the units from the numerator and the denominator:
- The effective numerator, after simplifying, has units of [tex]\(\frac{g}{L}\)[/tex].
- The denominator has units of [tex]\(\frac{g}{mol}\)[/tex].
5. Simplify the combined units:
- We now have [tex]\(\frac{g/L}{g/mol}\)[/tex].
- Dividing these units results in: [tex]\(\left(\frac{g}{L}\right) \times \left(\frac{mol}{g}\right) = \frac{mol}{L}\)[/tex].
Therefore, the resulting units for the student's answer are:
[tex]\[ \boxed{\frac{mol}{L}} \][/tex]