Select the correct answer.

Solve the following quadratic equation:

[tex](x-16)^2=256[/tex]

A. [tex]x=-32[/tex] and [tex]x=0[/tex]

B. [tex]x=30[/tex] and [tex]x=-4[/tex]

C. [tex]x=-30[/tex] and [tex]x=4[/tex]

D. [tex]x=32[/tex] and [tex]x=0[/tex]



Answer :

To solve the quadratic equation [tex]\((x - 16)^2 = 256\)[/tex], follow these detailed steps:

1. Understand the equation:
The equation is [tex]\((x - 16)^2 = 256\)[/tex].

2. Take the square root of both sides:
To remove the square, take the square root of both sides. Remember, taking the square root of a squared term introduces both positive and negative roots.
[tex]\[ \sqrt{(x - 16)^2} = \sqrt{256} \][/tex]
This simplifies to:
[tex]\[ x - 16 = \pm 16 \][/tex]

3. Solve the two resulting equations:
This step generates two separate equations:
[tex]\[ x - 16 = 16 \quad \text{and} \quad x - 16 = -16 \][/tex]

For the first equation:
[tex]\[ x - 16 = 16 \implies x = 16 + 16 = 32 \][/tex]

For the second equation:
[tex]\[ x - 16 = -16 \implies x = 16 - 16 = 0 \][/tex]

4. Combine the solutions:
The solutions are [tex]\( x = 32 \)[/tex] and [tex]\( x = 0 \)[/tex].

Therefore, the correct answer is:

D. [tex]\(x = 32\)[/tex] and [tex]\(x = 0\)[/tex]