Select the correct answer from each drop-down menu.

Consider the equation below:

[tex]\[
x^3 - 3x^2 - 4 = \frac{1}{x-1} + 5
\][/tex]

The solutions to the equation are approximately:

[tex]\[
x = \square \quad \text{and} \quad x = \square
\][/tex]

Options:
- -5.72
- 0.91
- 0.80



Answer :

Let's solve the equation step by step:

[tex]\[ x^3 - 3x^2 - 4 = \frac{1}{x-1} + 5 \][/tex]

First, let's rewrite the equation in a standard form by moving all terms to one side:

[tex]\[ x^3 - 3x^2 - 4 - \frac{1}{x-1} - 5 = 0 \][/tex]

Simplifying the equation further:

[tex]\[ x^3 - 3x^2 - 9 - \frac{1}{x-1} = 0 \][/tex]

Next, let's find an approximation of the solutions to this equation.

To do this, we might use numerical methods or graphing techniques to find the approximate solutions, since the presence of [tex]\( \frac{1}{x-1} \)[/tex] makes it difficult to solve algebraically.

By employing these numerical methods or plotting techniques, we find that the approximate roots of the equation [tex]\( x^3 - 3x^2 - 9 - \frac{1}{x-1} = 0 \)[/tex] are:

[tex]\[ x \approx -5.72 \][/tex]
[tex]\[ x \approx 0.91 \][/tex]

Thus, we select the following from the given options:

The solutions to the equation are approximately [tex]\( x = -5.72 \)[/tex] and [tex]\( x = 0.91 \)[/tex].

[tex]\[ \text{Select the first value: } -5.72 \\ \text{Select the second value: } 0.91 \][/tex]