First, let's calculate the amount of oxygen required for the given reaction using the stoichiometry of the reaction.
1. Calculate the moles of ethane:
Molar mass of ethane (C₂H₆) = 2*12 + 6*1 = 24 + 6 = 30g/mol
Number of moles of ethane = Mass of ethane / Molar mass of ethane
Number of moles of ethane = 120g / 30g/mol = 4 moles
2. Now we can use the balanced chemical equation to find the amount of oxygen required:
In the balanced equation:
2 moles of C₂H₆ react with 7 moles of O₂
So, 4 moles of C₂H₆ will react with:
(4 moles C₂H₆) * (7 moles O₂ / 2 moles C₂H₆) = 14 moles O₂
So, 14 moles of O₂ are required for the reaction.
3. Now, let's calculate the amount of carbon dioxide produced:
According to the balanced chemical equation:
2 moles of C₂H₆ produce 4 moles of CO₂
So, 4 moles of C₂H₆ will produce:
(4 moles C₂H₆) * (4 moles CO₂ / 2 moles C₂H₆) = 8 moles CO₂
4. Finally, let's convert the moles of carbon dioxide to grams using the molar mass:
Molar mass of CO₂ = 12 (C) + 16 (O) + 16 (O) = 44g/mol
Mass of carbon dioxide produced = Number of moles of CO₂ * Molar mass of CO₂
Mass of carbon dioxide produced = 8 moles * 44g/mol = 352g
So, 14 moles of oxygen are required for the reaction, and the reaction produces 352g of carbon dioxide.