Jessica solved the radical equation [tex]\sqrt{a-9} = 4[/tex]. Her math work is shown in the table below.

\begin{tabular}{|l|l|l|}
\hline \multicolumn{2}{|c|}{Step} & \multicolumn{1}{c|}{Justification} \\
\hline & [tex]\sqrt{a-9} = 4[/tex] & Given \\
\hline Step 1 & [tex](\sqrt{a-9})^2 = (4)^2[/tex] & Square both sides \\
\hline Step 2 & [tex]a-9 = 16[/tex] & Simplify \\
\hline Step 3 & [tex]a-9 + 9 = 16 + 9[/tex] & Add 9 to both sides \\
\hline Step 4 & [tex]a = 25[/tex] & Simplify \\
\hline Step 5 & [tex]25 - 9 \neq 4[/tex] & Check for extraneous solutions \\
\hline
\end{tabular}

In which step did Jessica make her first error?

A. Step 2

B. Step 3

C. Step 4

D. Step 5



Answer :

Jessica made her first error in Step 5. Here's a detailed explanation of each step and why Step 5 is incorrect:

- Step 1: [tex]\((\sqrt{a-9})^2 = (4)^2\)[/tex]

Justification: Square both sides of the equation to eliminate the square root. This step is valid.

- Step 2: [tex]\(a - 9 = 16\)[/tex]

Justification: Simplify the expression after squaring both sides. This step is valid.

- Step 3: [tex]\(a - 9 + 9 = 16 + 9\)[/tex]

Justification: Add 9 to both sides to isolate [tex]\(a\)[/tex]. This step is valid.

- Step 4: [tex]\(a = 25\)[/tex]

Justification: Simplify the equation to find the value of [tex]\(a\)[/tex]. This step is valid.

- Step 5: [tex]\(25 - 9 \neq 4\)[/tex]

Justification: This step is incorrect. When [tex]\(a = 25\)[/tex], we need to substitute back into the original equation to check for an extraneous solution. Substituting [tex]\(a = 25\)[/tex] into the original equation [tex]\(\sqrt{a-9}\)[/tex]:

[tex]\[ \sqrt{25 - 9} = \sqrt{16} = 4 \][/tex]

Since [tex]\(4 = 4\)[/tex], there is no extraneous solution, and [tex]\(a = 25\)[/tex] is correct. Therefore, her conclusion in Step 5 is incorrect.

Thus, Jessica made her first error in Step 5.