Answer :
Certainly! Let's solve the problem step-by-step:
1. Convert Mass to Kilograms:
- The mass of the baseball is given as 200 grams.
- To convert grams to kilograms, we use the conversion factor [tex]\(1 \text{ gram} = 0.001 \text{ kilograms}\)[/tex].
- Therefore, [tex]\(200 \text{ grams} \times 0.001 \text{ kg/gram} = 0.2 \text{ kilograms}\)[/tex].
2. Identify the Given Force:
- The force applied to the baseball is 2 Newtons (N) to the right.
3. Newton's Second Law of Motion:
- Newton's second law states that [tex]\(F = m \times a\)[/tex], where:
- [tex]\(F\)[/tex] is the net force applied to the object,
- [tex]\(m\)[/tex] is the mass of the object,
- [tex]\(a\)[/tex] is the acceleration of the object.
- From this formula, we can solve for acceleration ([tex]\(a\)[/tex]) using the equation [tex]\(a = \frac{F}{m}\)[/tex].
4. Calculate the Acceleration:
- Substitute the given values into the equation [tex]\(a = \frac{F}{m}\)[/tex]:
- The force [tex]\(F = 2 \text{ N}\)[/tex],
- The mass [tex]\(m = 0.2 \text{ kg}\)[/tex].
- Therefore, [tex]\(a = \frac{2 \text{ N}}{0.2 \text{ kg}} = 10 \text{ m/s}^2\)[/tex].
In conclusion, the acceleration of the baseball is [tex]\(10 \, \text{meters per second squared} (\text{m/s}^2)\)[/tex].
1. Convert Mass to Kilograms:
- The mass of the baseball is given as 200 grams.
- To convert grams to kilograms, we use the conversion factor [tex]\(1 \text{ gram} = 0.001 \text{ kilograms}\)[/tex].
- Therefore, [tex]\(200 \text{ grams} \times 0.001 \text{ kg/gram} = 0.2 \text{ kilograms}\)[/tex].
2. Identify the Given Force:
- The force applied to the baseball is 2 Newtons (N) to the right.
3. Newton's Second Law of Motion:
- Newton's second law states that [tex]\(F = m \times a\)[/tex], where:
- [tex]\(F\)[/tex] is the net force applied to the object,
- [tex]\(m\)[/tex] is the mass of the object,
- [tex]\(a\)[/tex] is the acceleration of the object.
- From this formula, we can solve for acceleration ([tex]\(a\)[/tex]) using the equation [tex]\(a = \frac{F}{m}\)[/tex].
4. Calculate the Acceleration:
- Substitute the given values into the equation [tex]\(a = \frac{F}{m}\)[/tex]:
- The force [tex]\(F = 2 \text{ N}\)[/tex],
- The mass [tex]\(m = 0.2 \text{ kg}\)[/tex].
- Therefore, [tex]\(a = \frac{2 \text{ N}}{0.2 \text{ kg}} = 10 \text{ m/s}^2\)[/tex].
In conclusion, the acceleration of the baseball is [tex]\(10 \, \text{meters per second squared} (\text{m/s}^2)\)[/tex].