```
[tex]$
\begin{array}{l}
\sqrt{-2x+1} = x + 3 \\
\sqrt{-2x+1} - 1 = x + 3 - 1 \\
\sqrt{-2x} = x + 2 \\
(\sqrt{-2x})^2 = (x + 2)^2 \\
-2x = x^2 + 4x + 4 \\
-2x + 2x = x^2 + 4x + 4 + 2x \\
0 = x^2 + 6x + 4 \\
0 = (x + 2)(x + 4) \\
x + 2 = 0 \\
x + 4 = 0 \\
x + 2 - 2 = 0 - 2 \\
x + 4 - 4 = 0 - 4 \\
x = -2 \\
x = -4 \\
\end{array}
$[/tex]

Both solutions are extraneous because they don't satisfy the original equation.

What error did Eloise make?

A. She factored [tex]$x^2 + 6x + 4$[/tex] incorrectly.
B. She did not check for extraneous solutions.
C. She subtracted 1 before squaring both sides.
D. She added [tex]$2x$[/tex] after squaring both sides.
```



Answer :

To address Eloise's error step by step, let's carefully examine her process and point out where things went wrong.

1. Given Equation:
[tex]\[ \sqrt{-2x + 1} = x + 3 \][/tex]

2. Transformed Equation:
Eloise transformed the equation:
[tex]\[ \sqrt{-2x + 1} - 1 = x + 3 - 1 \][/tex]
[tex]\[ \sqrt{-2x + 1} - 1 = x + 2 \][/tex]

3. Squaring Both Sides:
Eloise then squared both sides:
[tex]\[ (\sqrt{-2x + 1} - 1)^2 = (x + 2)^2 \][/tex]

Expanding both sides:
[tex]\[ (\sqrt{-2x + 1} - 1)^2 = -2x + 1 - 2\sqrt{-2x + 1} + 1 \][/tex]
[tex]\[ (x + 2)^2 = x^2 + 4x + 4 \][/tex]

4. Combining Terms:
[tex]\[ -2x + 1 - 2\sqrt{-2x + 1} + 1 = x^2 + 4x + 4 \][/tex]

5. Identification of the Error:
The key error in Eloise's method is revealed in Step 2. Eloise subtracted 1 from [tex]\(\sqrt{-2x + 1}\)[/tex] before squaring both sides.

This step:
[tex]\[ \sqrt{-2x + 1} - 1 = x + 3 - 1 \][/tex]
[tex]\[ \sqrt{-2x + 1} - 1 = x + 2 \][/tex]
should not have been performed. Instead, the squaring should have been directly applied to the original equation:
[tex]\[ (\sqrt{-2x + 1})^2 = (x + 3)^2 \][/tex]
This would have directly led to the correct transformed equation without introducing the extraneous terms.

To summarize:
The error Eloise made was subtracting 1 before squaring both sides of the equation. Therefore, the correct choice is:
She subtracted 1 before squaring both sides.