A picture is 7 inches wide and 9 inches long. A photographer enlarges it so it is 31.5 inches wide and 40.5 inches long. What scale factor was used to enlarge the picture?

A. [tex]\frac{9}{7}[/tex]
B. [tex]\frac{7}{9}[/tex]
C. [tex]\frac{31.5}{7}[/tex]
D. [tex]\frac{7}{31.5}[/tex]



Answer :

To determine the scale factor used to enlarge the picture, we need to compare the initial dimensions of the picture (width and length) with the enlarged dimensions.

### Step-by-Step Solution:

1. Initial Dimensions:
- Width: 7 inches
- Length: 9 inches

2. Enlarged Dimensions:
- Width: 31.5 inches
- Length: 40.5 inches

3. Calculate the Scale Factor for Width:
The scale factor for the width can be found by dividing the enlarged width by the initial width:
[tex]\[ \text{Scale factor for width} = \frac{31.5}{7} \][/tex]

4. Calculate the Scale Factor for Length:
Similarly, the scale factor for the length is found by dividing the enlarged length by the initial length:
[tex]\[ \text{Scale factor for length} = \frac{40.5}{9} \][/tex]

5. Verify the Scale Factors:
Both the width and length scale factors should be the same if the picture was enlarged proportionally.

Given the results:
- [tex]\(\frac{31.5}{7} = 4.5\)[/tex]
- [tex]\(\frac{40.5}{9} = 4.5\)[/tex]

Since both calculations give the same scale factor, we can confirm that the correct scale factor used to enlarge the picture is [tex]\(4.5\)[/tex].

### Answer:
The correct answer is:
[tex]\[ \frac{31.5}{7} \][/tex]

This corresponds to the scale factor [tex]\(4.5\)[/tex].