A group of agricultural students went on a field trip to the state fair. Each ticket to enter the fair was [tex]\$9[/tex] and the parking fee for the group's bus was [tex]\$25[/tex]. How many students went on the field trip if the total cost was [tex]\$313[/tex]?

Write an equation to represent this problem. Then solve the equation.

A. [tex]25 + 9x = 313; x = 32[/tex]
B. [tex]9x - 25 = 313; x = 38[/tex]
C. [tex]3x + 25 = 313; x = 32[/tex]
D. [tex]9x + 25 = 313; x = 32[/tex]



Answer :

To determine how many students went on the field trip, we need to set up an equation that takes into account the total cost, the cost of each student's ticket, and the parking fee for the bus.

Let's represent the number of students as [tex]\( x \)[/tex].

Each student’s ticket costs [tex]$9 and there is a fixed parking fee of $[/tex]25 for the bus. The total cost for the trip is given as $313.

We can write an equation to represent this situation:
[tex]\[ 9x + 25 = 313 \][/tex]

Here's the step-by-step solution to solve for [tex]\( x \)[/tex]:

1. Subtract the parking fee from the total cost:

[tex]\[ 313 - 25 = 288 \][/tex]

This calculation isolates the total cost of the students' tickets.

2. Divide the remaining cost by the cost per student ticket:

[tex]\[ x = \frac{288}{9} \][/tex]

[tex]\[ x = 32 \][/tex]

So, the number of students who went on the field trip is 32.

Therefore, the correct answer is:
[tex]\[ B. \ 9x + 25 = 313; \ x = 32 \][/tex]