Answer :
To determine Mr. Ghimire's monthly income based on the information provided, we can follow a step-by-step approach. Here are the details:
1. Identify the fraction of income spent:
Mr. Ghimire spends [tex]\(\frac{7}{10}\)[/tex] parts of his total income.
2. Determine the amount spent:
It is given that the amount Mr. Ghimire spends, which corresponds to [tex]\(\frac{7}{10}\)[/tex] parts of his income, is RS 28000.
3. Set up the relationship:
Let [tex]\(x\)[/tex] be Mr. Ghimire's total monthly income. According to the given information, [tex]\(\frac{7}{10}\)[/tex] of [tex]\(x\)[/tex] is equal to RS 28000.
[tex]\[ \frac{7}{10}x = 28000 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
To find [tex]\(x\)[/tex], we need to isolate it on one side of the equation. To do this, multiply both sides of the equation by the reciprocal of [tex]\(\frac{7}{10}\)[/tex], which is [tex]\(\frac{10}{7}\)[/tex].
[tex]\[ x = 28000 \times \frac{10}{7} \][/tex]
5. Calculate the value of [tex]\(x\)[/tex]:
[tex]\[ x = 28571.4286 \times 1.4286 = 40000 \][/tex]
Therefore, Mr. Ghimire's monthly income is RS 40000.
1. Identify the fraction of income spent:
Mr. Ghimire spends [tex]\(\frac{7}{10}\)[/tex] parts of his total income.
2. Determine the amount spent:
It is given that the amount Mr. Ghimire spends, which corresponds to [tex]\(\frac{7}{10}\)[/tex] parts of his income, is RS 28000.
3. Set up the relationship:
Let [tex]\(x\)[/tex] be Mr. Ghimire's total monthly income. According to the given information, [tex]\(\frac{7}{10}\)[/tex] of [tex]\(x\)[/tex] is equal to RS 28000.
[tex]\[ \frac{7}{10}x = 28000 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
To find [tex]\(x\)[/tex], we need to isolate it on one side of the equation. To do this, multiply both sides of the equation by the reciprocal of [tex]\(\frac{7}{10}\)[/tex], which is [tex]\(\frac{10}{7}\)[/tex].
[tex]\[ x = 28000 \times \frac{10}{7} \][/tex]
5. Calculate the value of [tex]\(x\)[/tex]:
[tex]\[ x = 28571.4286 \times 1.4286 = 40000 \][/tex]
Therefore, Mr. Ghimire's monthly income is RS 40000.