Answer :

Certainly! Let's go through each multiplication step-by-step using the column method.

### Part A: [tex]\(275 \times 15\)[/tex]

1. Multiply 275 by 5 (units place of 15):
[tex]\[ \begin{array}{r} 275 \\ \times\ 5 \\ \hline 1375 \\ \end{array} \][/tex]
Result: 1375 (Units place multiplication)

2. Multiply 275 by 10 (tens place of 15):
[tex]\[ \begin{array}{r} 2750 \\ \end{array} \][/tex]
Result: 2750 (Tens place multiplication)

3. Add both intermediate results:
[tex]\[ \begin{array}{r} 1375 \\ + 2750 \\ \hline 4125 \\ \end{array} \][/tex]
Final result: 4125

### Part B: [tex]\(2,151 \times 12\)[/tex]

1. Multiply 2151 by 2 (units place of 12):
[tex]\[ \begin{array}{r} 2151 \\ \times\ 2 \\ \hline 4302 \\ \end{array} \][/tex]
Result: 4302 (Units place multiplication)

2. Multiply 2151 by 10 (tens place of 12):
[tex]\[ \begin{array}{r} 21510 \\ \end{array} \][/tex]
Result: 21510 (Tens place multiplication)

3. Add both intermediate results:
[tex]\[ \begin{array}{r} 4302 \\ + 21510 \\ \hline 25812 \\ \end{array} \][/tex]
Final result: 25812

### Part C: [tex]\(639 \times 23\)[/tex]

1. Multiply 639 by 3 (units place of 23):
[tex]\[ \begin{array}{r} 639 \\ \times\ 3 \\ \hline 1917 \\ \end{array} \][/tex]
Result: 1917 (Units place multiplication)

2. Multiply 639 by 20 (tens place of 23):
[tex]\[ \begin{array}{r} 12780 \\ \end{array} \][/tex]
Result: 12780 (Tens place multiplication)

3. Add both intermediate results:
[tex]\[ \begin{array}{r} 1917 \\ + 12780 \\ \hline 14697 \\ \end{array} \][/tex]
Final result: 14697

By following these steps, we get:
- The result of [tex]\(275 \times 15\)[/tex] is 4125.
- The result of [tex]\(2,151 \times 12\)[/tex] is 25812.
- The result of [tex]\(639 \times 23\)[/tex] is 14697.