Question 1:

Calculate the water level in the burette.

[tex]\[ 88 \times 0.25 = 22 \][/tex]
[tex]\[ + \frac{27}{4^9} \][/tex]
[tex]\[ = 49 \, \text{cm}^3 \][/tex]

Question 2:

A thin wire was wound 30 times closely over a boiling tube. The total length of the windings was found to be 9.3 mm. Calculate the radius of the wire.

[tex]\[ \frac{9.3}{10} = 0.93 \][/tex]
[tex]\[ 2 \times \frac{22 \times 1}{7} = 0.93 \times \frac{7}{44} \][/tex]
[tex]\[ \frac{0.93 \times 7}{44} = 0.147 \][/tex]

(Note: The final expression is not clear and may need further context or clarification to ensure accuracy in the calculations.)



Answer :

To solve this problem, we need to determine the radius of the wire that has been wound 30 times around a boiling tube. The total length of the windings is given as 9.3 mm.

### Step-by-Step Solution:

1. Convert the total length to centimeters:
Since the total length is given in millimeters and we often use centimeters for such measurements, we convert 9.3 mm to centimeters. We know that 1 cm = 10 mm. Therefore:
[tex]\[ \text{Total length in cm} = \frac{9.3 \text{ mm}}{10} = 0.93 \text{ cm} \][/tex]

2. Identify that the total length of the wire is related to the circumference of each winding.
Each winding can be considered a circle with a certain radius, and the circumference of a circle is given by the formula:
[tex]\[ \text{Circumference} = 2 \pi \times \text{radius} \][/tex]

3. Establish the relationship between the total length and the number of windings:
Given that the wire is wound 30 times, the total length of the wire is the sum of the circumferences of all windings. Thus:
[tex]\[ \text{Total length} = \text{Number of windings} \times \text{Circumference of one winding} \][/tex]
Plugging in the values we have:
[tex]\[ 0.93 \text{ cm} = 30 \times (2 \pi \times \text{radius}) \][/tex]

4. Solve for the radius:
To find the radius, we rearrange the formula to solve for the radius:
[tex]\[ \text{radius} = \frac{\text{Total length}}{30 \times 2 \pi} \][/tex]
Substitute the known values:
[tex]\[ \text{radius} = \frac{0.93 \text{ cm}}{30 \times 2 \pi} \][/tex]
We know that [tex]\(\pi \approx 3.14159\)[/tex].

5. Numerical solution:
Plugging in the value of [tex]\(\pi\)[/tex]:
[tex]\[ \text{radius} = \frac{0.93}{30 \times 2 \times 3.14159} \approx \frac{0.93}{188.4955} \][/tex]
Performing the division gives:
[tex]\[ \text{radius} \approx 0.0049338 \text{ cm} \][/tex]

### Summary:
- The total length of the wire in centimeters is [tex]\(0.93 \, \text{cm}\)[/tex].
- The radius of the wire is approximately [tex]\(0.0049338 \, \text{cm}\)[/tex] or [tex]\(4.9338 \, \text{mm}\)[/tex].

Therefore, we have:
[tex]\[ \boxed{0.93 \text{ cm}, \ 0.0049338 \text{ cm}} \][/tex]
which implies that the radius of the wire is approximately [tex]\(0.49338 \, \text{mm}\)[/tex].