Let's first rectify and understand the problem statement:
"The sum of two consecutive whole numbers is 19. Find the greatest number of [tex]$50."
### Step-by-Step Solution:
1. Identify Variables and Equations:
Let the two consecutive whole numbers be \( n \) and \( n+1 \).
Their sum can be written as:
\[
n + (n + 1) = 19
\]
2. Simplify the Equation:
Combine like terms:
\[
n + n + 1 = 19
\]
\[
2n + 1 = 19
\]
3. Solve for \( n \):
Subtract 1 from both sides to isolate terms with \( n \):
\[
2n = 18
\]
Divide both sides by 2:
\[
n = 9
\]
So, the two consecutive whole numbers are \( 9 \) and \( 10 \).
4. Interpret the Additional Part of the Problem:
Now, based on the fixed math steps, the problem then asks to find the greatest number among the given options when applied to some transformation involving $[/tex]50.
The provided answer options are:
- A) 300
- B) 400
- C) 200
- D) 500
5. Determine the Greatest Number from Given Options:
That's straightforward, we just need to identify the greatest number from the list directly:
- Among A) 300, B) 400, C) 200, D) 500, the greatest number is obviously:
[tex]\[
\boxed{500}
\][/tex]
So, the greatest number of [tex]$50 y s$[/tex] is indeed 500.
