Which equations have the same value of [tex]$x$[/tex] as [tex]\frac{2}{3}(6x+12)=-24[/tex]?

Select two options.

A. [tex]4x + 8 = -24[/tex]

B. [tex]9x + 18 = -24[/tex]

C. [tex]4x = -16[/tex]

D. [tex]\frac{18x + 36}{2} = -24[/tex]

E. [tex]4x = -32[/tex]



Answer :

To determine which equations have the same value of [tex]\( x \)[/tex] as the given equation [tex]\(\frac{2}{3}(6x + 12) = -24 \)[/tex], we need to follow these steps:

1. Solve the given equation [tex]\(\frac{2}{3}(6x + 12) = -24\)[/tex] to find the value of [tex]\( x \)[/tex]:

[tex]\[ \frac{2}{3}(6x + 12) = -24 \][/tex]

First, eliminate the fraction by multiplying both sides by [tex]\(\frac{3}{2}\)[/tex]:

[tex]\[ 6x + 12 = -24 \times \frac{3}{2} \][/tex]

Simplify the right side:

[tex]\[ 6x + 12 = -36 \][/tex]

Next, solve for [tex]\( x \)[/tex] by isolating the variable:

[tex]\[ 6x = -36 - 12 \][/tex]

[tex]\[ 6x = -48 \][/tex]

[tex]\[ x = \frac{-48}{6} \][/tex]

[tex]\[ x = -8 \][/tex]

So, the value of [tex]\( x \)[/tex] is [tex]\( -8 \)[/tex].

2. Check each proposed equation to see if they yield the same value of [tex]\( x \)[/tex]:

Let's analyze each equation one by one and see if they provide [tex]\( x = -8 \)[/tex].

#### Option 1: [tex]\( 4x + 8 = -24 \)[/tex]

Substitute [tex]\( x = -8 \)[/tex]:

[tex]\[ 4(-8) + 8 = -32 + 8 = -24 \][/tex]

This is a correct equation, as it holds true for [tex]\( x = -8 \)[/tex].

#### Option 2: [tex]\( 9x + 18 = -24 \)[/tex]

Substitute [tex]\( x = -8 \)[/tex]:

[tex]\[ 9(-8) + 18 = -72 + 18 = -54 \][/tex]

This equation does NOT hold true for [tex]\( x = -8 \)[/tex].

#### Option 3: [tex]\( 4x = -16 \)[/tex]

Substitute [tex]\( x = -8 \)[/tex]:

[tex]\[ 4(-8) = -32 \][/tex]

This equation does NOT hold true for [tex]\( x = -8 \)[/tex].

#### Option 4: [tex]\( \frac{18x + 36}{2} = -24 \)[/tex]

Substitute [tex]\( x = -8 \)[/tex]:

[tex]\[ \frac{18(-8) + 36}{2} = \frac{-144 + 36}{2} = \frac{-108}{2} = -54 \][/tex]

This equation does NOT hold true for [tex]\( x = -8 \)[/tex].

#### Option 5: [tex]\( 4x = -32 \)[/tex]

Substitute [tex]\( x = -8 \)[/tex]:

[tex]\[ 4(-8) = -32 \][/tex]

This is a correct equation, as it holds true for [tex]\( x = -8 \)[/tex].

Therefore, the two equations that have the same value of [tex]\( x \)[/tex] as the given equation [tex]\(\frac{2}{3}(6x + 12) = -24\)[/tex] are:

- [tex]\( 4x + 8 = -24 \)[/tex]
- [tex]\( 4x = -32 \)[/tex]

These correspond to options 1 and 5.