Select the correct answer.

Function [tex]$h$[/tex] has an [tex]$x$[/tex]-intercept at [tex]$(4,0)$[/tex]. Which statement must be true about [tex]$D$[/tex], the discriminant of function [tex]$h$[/tex]?

A. [tex]$D \ \textless \ 0$[/tex]
B. [tex]$D \geq 0$[/tex]
C. [tex]$D = 0$[/tex]
D. [tex]$D \ \textgreater \ 0$[/tex]



Answer :

To determine which statement must be true about [tex]\( D \)[/tex], the discriminant of function [tex]\( h \)[/tex], given that function [tex]\( h \)[/tex] has an [tex]\( x \)[/tex]-intercept at [tex]\((4,0)\)[/tex], let's recall some key concepts about the discriminant and roots of quadratic functions.

1. Understanding the Discriminant:
- For a quadratic equation of the form [tex]\( ax^2 + bx + c = 0 \)[/tex], the discriminant, [tex]\( D \)[/tex], is given by the formula:
[tex]\[ D = b^2 - 4ac \][/tex]
- The discriminant helps us determine the nature of the roots of the quadratic equation:
- If [tex]\( D > 0 \)[/tex], there are two distinct real roots.
- If [tex]\( D = 0 \)[/tex], there is exactly one real root (a repeated root).
- If [tex]\( D < 0 \)[/tex], there are no real roots (the roots are complex or imaginary).

2. Examining the Given Information:
- The function [tex]\( h \)[/tex] has an [tex]\( x \)[/tex]-intercept at [tex]\( (4,0) \)[/tex]. This means that the function crosses the [tex]\( x \)[/tex]-axis at [tex]\( x = 4 \)[/tex].
- An [tex]\( x \)[/tex]-intercept indicates that there is at least one real root of the function [tex]\( h(x) = 0 \)[/tex].

3. Implications for the Discriminant [tex]\( D \)[/tex]:
- Since the function [tex]\( h \)[/tex] has at least one real root, the discriminant [tex]\( D \)[/tex] cannot be negative because negative discriminants correspond to no real roots.
- Therefore, the discriminant [tex]\( D \)[/tex] must be non-negative.

From this reasoning, the appropriate statement about [tex]\( D \)[/tex] is:
[tex]\[ \boxed{B. \, D \geq 0} \][/tex]