Answer:
-1
Step-by-step explanation:
You want the mean of (-10-2i) and (8+2i).
Average
The mean (average) of two numbers is half their sum:
[tex]m=\dfrac{(-10-2i)+(8+2i)}{2}=\dfrac{-10+8}{2}+\dfrac{-2+2}{2}i\\\\\\m=-\dfrac{2}{2}+\dfrac{0}{2}i=\boxed{-1}[/tex]
The average of z₁ and z₂ is -1.
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Additional comment
If you need the imaginary part shown, you could write it as m = -1 +0i.
