Answer :
Let's solve the quadratic equation [tex]\(x^2 + 2x = -2\)[/tex].
1. Rearrange the equation: Start by bringing all terms to one side to set the equation to zero.
[tex]\[ x^2 + 2x + 2 = 0 \][/tex]
2. Identify the coefficients: This is a standard quadratic equation of the form [tex]\(ax^2 + bx + c = 0\)[/tex], where:
[tex]\[ a = 1, \quad b = 2, \quad c = 2 \][/tex]
3. Calculate the discriminant: The discriminant [tex]\(\Delta\)[/tex] of a quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
Substituting the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]:
[tex]\[ \Delta = (2)^2 - 4(1)(2) = 4 - 8 = -4 \][/tex]
4. Determine the nature of the roots: The discriminant [tex]\(\Delta = -4\)[/tex] is less than zero, indicating that the roots are complex (non-real) and conjugate pairs.
5. Find the roots using the quadratic formula: The quadratic formula for finding roots of [tex]\(ax^2 + bx + c = 0\)[/tex] is:
[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]
Since [tex]\(\Delta = -4\)[/tex], we can write [tex]\(\sqrt{\Delta} = \sqrt{-4} = 2i\)[/tex]. Therefore:
[tex]\[ x = \frac{-2 \pm 2i}{2(1)} = \frac{-2 \pm 2i}{2} = -1 \pm i \][/tex]
6. State the solutions: The solutions to the equation [tex]\(x^2 + 2x = -2\)[/tex] are:
[tex]\[ x = -1 - i \quad \text{and} \quad x = -1 + i \][/tex]
Comparing these solutions with the given options:
- A. [tex]\(x = 1 \pm i\)[/tex]
- B. [tex]\(x = -1 \pm 1\)[/tex]
- C. [tex]\(x = 0\)[/tex]
- D. [tex]\(x = \pm 1\)[/tex]
The correct answer is not explicitly listed in the options you provided. However, if we closely observe, our solutions [tex]\(x = -1 - i\)[/tex] and [tex]\(x = -1 + i\)[/tex] include a complex number [tex]\(i\)[/tex].
Nevertheless, let's carefully conclude the correct answer:
The solution matches the form of [tex]\(-1 \pm i\)[/tex], which unfortunately isn't listed as an explicit option here. So if you provided me complete incorrect set of answers, A would be the closest relevant, but have errors. Given properly correct options, there will be an option explicitly indicating [tex]\(-1 \pm i\)[/tex].
Without any clearly correct selectable option, it seems to be improper information formulating around. Problems could be in choices here.
This leaves need of refurnishment to precise answers listing.
1. Rearrange the equation: Start by bringing all terms to one side to set the equation to zero.
[tex]\[ x^2 + 2x + 2 = 0 \][/tex]
2. Identify the coefficients: This is a standard quadratic equation of the form [tex]\(ax^2 + bx + c = 0\)[/tex], where:
[tex]\[ a = 1, \quad b = 2, \quad c = 2 \][/tex]
3. Calculate the discriminant: The discriminant [tex]\(\Delta\)[/tex] of a quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
Substituting the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]:
[tex]\[ \Delta = (2)^2 - 4(1)(2) = 4 - 8 = -4 \][/tex]
4. Determine the nature of the roots: The discriminant [tex]\(\Delta = -4\)[/tex] is less than zero, indicating that the roots are complex (non-real) and conjugate pairs.
5. Find the roots using the quadratic formula: The quadratic formula for finding roots of [tex]\(ax^2 + bx + c = 0\)[/tex] is:
[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]
Since [tex]\(\Delta = -4\)[/tex], we can write [tex]\(\sqrt{\Delta} = \sqrt{-4} = 2i\)[/tex]. Therefore:
[tex]\[ x = \frac{-2 \pm 2i}{2(1)} = \frac{-2 \pm 2i}{2} = -1 \pm i \][/tex]
6. State the solutions: The solutions to the equation [tex]\(x^2 + 2x = -2\)[/tex] are:
[tex]\[ x = -1 - i \quad \text{and} \quad x = -1 + i \][/tex]
Comparing these solutions with the given options:
- A. [tex]\(x = 1 \pm i\)[/tex]
- B. [tex]\(x = -1 \pm 1\)[/tex]
- C. [tex]\(x = 0\)[/tex]
- D. [tex]\(x = \pm 1\)[/tex]
The correct answer is not explicitly listed in the options you provided. However, if we closely observe, our solutions [tex]\(x = -1 - i\)[/tex] and [tex]\(x = -1 + i\)[/tex] include a complex number [tex]\(i\)[/tex].
Nevertheless, let's carefully conclude the correct answer:
The solution matches the form of [tex]\(-1 \pm i\)[/tex], which unfortunately isn't listed as an explicit option here. So if you provided me complete incorrect set of answers, A would be the closest relevant, but have errors. Given properly correct options, there will be an option explicitly indicating [tex]\(-1 \pm i\)[/tex].
Without any clearly correct selectable option, it seems to be improper information formulating around. Problems could be in choices here.
This leaves need of refurnishment to precise answers listing.