Answer :
Certainly! Let's start with the ionization reactions for the given acids:
1. Ionization Reactions for Acids
1.1. [tex]$HNO_3$[/tex] (Nitric Acid):
Nitric acid is a strong acid and fully ionizes in water. The ionization reaction is:
[tex]\[ HNO_3 (aq) \rightarrow H^+ (aq) + NO_3^- (aq) \][/tex]
1.2. [tex]$CH_3COOH$[/tex] (Acetic Acid):
Acetic acid is a weak acid and partially ionizes in water. The ionization reaction is:
[tex]\[ CH_3COOH (aq) \rightleftharpoons H^+ (aq) + CH_3COO^- (aq) \][/tex]
Note the reversible reaction arrow, indicating partial ionization.
1.3. [tex]$H_3PO_4$[/tex] (Phosphoric Acid):
Phosphoric acid is a weak triprotic acid, meaning it can lose three protons in steps. The ionization reactions are:
First ionization:
[tex]\[ H_3PO_4 (aq) \rightleftharpoons H^+ (aq) + H_2PO_4^- (aq) \][/tex]
Second ionization:
[tex]\[ H_2PO_4^- (aq) \rightleftharpoons H^+ (aq) + HPO_4^{2-} (aq) \][/tex]
Third ionization:
[tex]\[ HPO_4^{2-} (aq) \rightleftharpoons H^+ (aq) + PO_4^{3-} (aq) \][/tex]
2. Dissociation Reactions for the given problem are not provided within this part. Let's focus entirely on the given ions.
I hope this helps with your understanding of acid ionization reactions! If you have any follow-up questions or further problems to address, feel free to ask.
1. Ionization Reactions for Acids
1.1. [tex]$HNO_3$[/tex] (Nitric Acid):
Nitric acid is a strong acid and fully ionizes in water. The ionization reaction is:
[tex]\[ HNO_3 (aq) \rightarrow H^+ (aq) + NO_3^- (aq) \][/tex]
1.2. [tex]$CH_3COOH$[/tex] (Acetic Acid):
Acetic acid is a weak acid and partially ionizes in water. The ionization reaction is:
[tex]\[ CH_3COOH (aq) \rightleftharpoons H^+ (aq) + CH_3COO^- (aq) \][/tex]
Note the reversible reaction arrow, indicating partial ionization.
1.3. [tex]$H_3PO_4$[/tex] (Phosphoric Acid):
Phosphoric acid is a weak triprotic acid, meaning it can lose three protons in steps. The ionization reactions are:
First ionization:
[tex]\[ H_3PO_4 (aq) \rightleftharpoons H^+ (aq) + H_2PO_4^- (aq) \][/tex]
Second ionization:
[tex]\[ H_2PO_4^- (aq) \rightleftharpoons H^+ (aq) + HPO_4^{2-} (aq) \][/tex]
Third ionization:
[tex]\[ HPO_4^{2-} (aq) \rightleftharpoons H^+ (aq) + PO_4^{3-} (aq) \][/tex]
2. Dissociation Reactions for the given problem are not provided within this part. Let's focus entirely on the given ions.
I hope this helps with your understanding of acid ionization reactions! If you have any follow-up questions or further problems to address, feel free to ask.