Several students measured the mass of a rabbit and recorded their measurements in a table.

\begin{tabular}{|l|l|}
\hline
Student 1 & [tex]$1.6\ \text{kg}=1,600\ \text{g}$[/tex] \\
\hline
Student 2 & [tex]$2,300\ \text{g}$[/tex] \\
\hline
Student 3 & Between [tex]$1,000$[/tex] and [tex]$1,500\ \text{g}$[/tex] \\
\hline
Student 4 & [tex]$1,750\ \text{g}$[/tex] \\
\hline
\end{tabular}

The actual mass of the rabbit is [tex]$1,864.3\ \text{g}$[/tex]. Which statement best describes the accuracy and precision of their data?

A. Accurate but not precise
B. Precise but not accurate
C. Both accurate and precise
D. Neither accurate nor precise



Answer :

Let's analyze the students' measurements and determine the accuracy and precision of the data.

1. Converting Measurements:
- Student 1: 1.6 kg = 1,600 g
- Student 2: 2,300 g
- Student 3: Between 1,000 and 1,500 g → We'll use the midpoint, so (1000+1500)/2 = 1,375 g
- Student 4: 1,750 g

The measurements are:
[tex]\[ [1600, 2300, 1375, 1750] \][/tex]

2. Calculate the Mean of Measurements:
The mean is calculated by summing all measurements and dividing by the number of measurements:
[tex]\[ \text{Mean} = \frac{1600 + 2300 + 1375 + 1750}{4} = \frac{7025}{4} = 1756.25 \text{ g} \][/tex]

3. Calculate the Variance:
Variance is a measure of how much the measurements spread out from the mean. It’s calculated by averaging the squared differences from the mean:
[tex]\[ \text{Variance} = \frac{(1600 - 1756.25)^2 + (2300 - 1756.25)^2 + (1375 - 1756.25)^2 + (1750 - 1756.25)^2}{4} \][/tex]
[tex]\[ = \frac{(-156.25)^2 + 543.75^2 + (-381.25)^2 + (-6.25)^2}{4} = \frac{24390.625 + 295662.1875 + 145351.5625 + 39.0625}{4} = \frac{465443.4375}{4} = 116367.1875 \text{ g}^2 \][/tex]

4. Calculate the Standard Deviation:
The standard deviation is the square root of the variance:
[tex]\[ \text{Standard Deviation (Precision)} = \sqrt{116367.1875} \approx 341.13 \text{ g} \][/tex]

5. Calculate the Accuracy:
Accuracy is determined by the absolute difference between the mean of the measurements and the actual mass:
[tex]\[ \text{Accuracy} = |\text{Mean} - \text{Actual Mass}| = |1756.25 - 1864.3| = 108.05 \text{ g} \][/tex]

6. Analyzing Accuracy and Precision:
- Precision: The standard deviation of 341.13 g is quite large, indicating the measurements are not very close to each other.
- Accuracy: The accuracy of 108.05 g is moderately large, indicating the mean of the measurements is not very close to the actual mass.

Given these calculations,
- The accuracy (108.05 g) is greater than 100 g.
- The precision (341.13 g) is also greater than 100 g.

Thus, the best fit description for the measurements is:
[tex]\[ \boxed{D. \text{Neither accurate nor precise}} \][/tex]